The stopcock connecting a l.13 L bulb containing xenon gas at a pressure of 5.08 atm, and a 4.71 L bulb containing krypton gas at a pressure of 1.31 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, the final pressure in the system is atm

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### Gas Laws and Mixing Gases: A Practical Application

**Problem Statement**:
The stopcock connecting a 1.13 L bulb containing xenon gas at a pressure of 5.08 atm, and a 4.71 L bulb containing krypton gas at a pressure of 1.31 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, the final pressure in the system is ______ atm.

**Solution Attempts**:
There are interactive buttons indicated for multiple submission attempts:
- **Submit Answer**
- **Retry Entire Group**
- It also notes that there are 9 more group attempts remaining.

**Explanation**:
To find the final pressure in the system after the gases have been allowed to mix, we can use the combined gas law. Since the temperature remains constant, we can apply Dalton's Law of Partial Pressures. Dalton's Law states:

\[ P_{final} = \frac{(P_1 \times V_1) + (P_2 \times V_2)}{V_{total}} \]

Where:
- \( P_1 \) and \( V_1 \) are the initial pressure and volume of xenon gas
- \( P_2 \) and \( V_2 \) are the initial pressure and volume of krypton gas
- \( V_{total} \) is the total volume of the mixed gases

**Given Data**:
- \( P_1 \) (Xenon gas pressure) = 5.08 atm
- \( V_1 \) (Xenon gas volume) = 1.13 L
- \( P_2 \) (Krypton gas pressure) = 1.31 atm
- \( V_2 \) (Krypton gas volume) = 4.71 L
- \( V_{total} \) = \( V_1 + V_2 \) = 1.13 L + 4.71 L = 5.84 L

**Calculation**:
\[ P_{final} = \frac{(5.08 \times 1.13) + (1.31 \times 4.71)}{5.84} \]

Let's compute the values:
\[ P_{final} = \frac{(5.7404) + (6.1701)}{5.84} \]
\[ P_{final} = \frac{11
Transcribed Image Text:### Gas Laws and Mixing Gases: A Practical Application **Problem Statement**: The stopcock connecting a 1.13 L bulb containing xenon gas at a pressure of 5.08 atm, and a 4.71 L bulb containing krypton gas at a pressure of 1.31 atm, is opened and the gases are allowed to mix. Assuming that the temperature remains constant, the final pressure in the system is ______ atm. **Solution Attempts**: There are interactive buttons indicated for multiple submission attempts: - **Submit Answer** - **Retry Entire Group** - It also notes that there are 9 more group attempts remaining. **Explanation**: To find the final pressure in the system after the gases have been allowed to mix, we can use the combined gas law. Since the temperature remains constant, we can apply Dalton's Law of Partial Pressures. Dalton's Law states: \[ P_{final} = \frac{(P_1 \times V_1) + (P_2 \times V_2)}{V_{total}} \] Where: - \( P_1 \) and \( V_1 \) are the initial pressure and volume of xenon gas - \( P_2 \) and \( V_2 \) are the initial pressure and volume of krypton gas - \( V_{total} \) is the total volume of the mixed gases **Given Data**: - \( P_1 \) (Xenon gas pressure) = 5.08 atm - \( V_1 \) (Xenon gas volume) = 1.13 L - \( P_2 \) (Krypton gas pressure) = 1.31 atm - \( V_2 \) (Krypton gas volume) = 4.71 L - \( V_{total} \) = \( V_1 + V_2 \) = 1.13 L + 4.71 L = 5.84 L **Calculation**: \[ P_{final} = \frac{(5.08 \times 1.13) + (1.31 \times 4.71)}{5.84} \] Let's compute the values: \[ P_{final} = \frac{(5.7404) + (6.1701)}{5.84} \] \[ P_{final} = \frac{11
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