The state test scores for 12 randomly selected high school seniors are shown on the right. Complete parts (a) through (c)below.Assume the population is normally distributed.(a) Find the sample mean.x= (Round to one decimal place as needed.)(b) Find the sample standard deviation.s = (Round to one decimal place as needed.)(c) Construct a 99% confidence interval for the population mean μ.A 99% confidence interval for the population mean is (.).(Round to one decimal place as needed.)C142469472962512257257421449984835548943T

The provided 12 sample observations (i.e., the sample size, n=12) are : 1424, 694, 729, 625, 1225,…

Answered: The state test scores for 12 randomly…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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I need the sample mean and the sample standard deviation.
A population has a mean μ=88 and a standard deviation σ=28. Find the mean and standard deviation of a sampling distribution of sample means with sample size n=49. μx= (Simplify your answer.)
Identify the symbols used for each of the following: (a) sample standard deviation; (b) population standard deviation; (c) sample variance; (d) population variance. a. The symbol for sample standard deviation is b. The symbol for population standard deviation is c. The symbol for sample variance is d. The symbol for population variance is
Suppose you take a random sample of n = 80 Douglas College students and ask each student their age. You find that the mean age of students in this sample is X = 22.0375 years and the sample standard deviation is s = 3.2014 years. Fill in the blanks (rounding to four decimal places): The 95% confidence interval for the mean age μ of all Douglas College students is from ______ years to ______ years.
statistics practitioner took a random sample of 48 observations from a population whose standard deviation is 23 and computed the sample mean to be 100. Note: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the parentheses and the comma between the confidence limits. A. Estimate the population mean with 95% confidence. Confidence Interval = B. Estimate the population mean with 95% confidence, changing the population standard deviation to 47; Confidence Interval = C. Estimate the population mean with 95% confidence, changing the population standard deviation to 10; Confidence Interval =
Tina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.
A population has a mean µ = 87 and a standard deviation o=27. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 81. (Simplify your answer.)
4000 B.C. A.D. 150 A study was done on skull sizes of humans during different time periods. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. H2 27 27 131.05 mm 133.94 mm S 5.18 mm 5.27 mm a. Use a 0.05 significance level to test the claim that the mean skull breadth in 4000 B.C is less than the mean skull breadth in A.D 150. What are the null and alternative hypotheses? O B. Ho: H1 =H2 O A. Ho: H1 =H2 H:H1> H2 OC. Ho: H1 = H2 H1: H1 # H2 O D. Ho: H1 # H2 H: H1
Consider the following sample data. Sample A: 11, 22, 33 Sample B: 81, 92, 103 Sample C: 1,100; 1,111; 1,122 (a) Find the mean and standard deviation for each sample. Sample A: Sample B: Sample C: Mean Sample Standard Deviation (b) What does this exercise show about the standard deviation? multiple choice The idea is to illustrate that the standard deviation is not a function of the value of the mean. The idea is to illustrate that the standard deviation is a function of the value of the mean.

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