The standard reaction free energy AG°=-1181. kJ for this reaction: 4 H2O2(1) + PbS(s)→P6SO4(s) + 4 H,0(1) Use this information to complete the table below. Round each of your answers to the nearest kJ. aG reaction Poso,6) + H,0() - 4,0,0) + Pos() PbSO,(s) + 4H,0(1) → 4H,0,(1) + PbS (s) 1 1 H,0,() + PbS (-) - PbsO,6,) + H,0()
The standard reaction free energy AG°=-1181. kJ for this reaction: 4 H2O2(1) + PbS(s)→P6SO4(s) + 4 H,0(1) Use this information to complete the table below. Round each of your answers to the nearest kJ. aG reaction Poso,6) + H,0() - 4,0,0) + Pos() PbSO,(s) + 4H,0(1) → 4H,0,(1) + PbS (s) 1 1 H,0,() + PbS (-) - PbsO,6,) + H,0()
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:The standard reaction free energy AG =-1181. kJ for this reaction:
4 H,02(1) + PbS(s)→PbSO4(s) + 4 H2O(1)
Use this information to complete the table below. Round each of your answers to the nearest kJ.
reaction
х10
1
Poso,6) + 4,0() - 4,0,) + Pos()
- PbSo,(s)
3 H,0(1)
3 H,0,(1) +
- PbS(s)
O kJ
PbSo, (s) + 4H,0() → 4H,0,(1) + Pbs(s)
4H,0,(1) + PbS(s)
kJ
H,0,(1) +
PbS (s)
i Pbso,(4) + H,0()
| kJ
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