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The standard equation of the sphere that has center (1,-2,1) and passing through the origin, is given by Px+1)²+(y-2)²+ (z – 1)² =6 Ox +1)2+(y-2)²+ (z – 1)² = 36 O (x-1)2 +(y+2)² + (z–1)² =6 (x-1)? +(y+2)² + (z+1)? = /6

The standard equation of the sphere that has center (1,-2,1) and passing through the origin, is given by Px+1)²+(y-2)²+ (z – 1)² =6 Ox +1)2+(y-2)²+ (z – 1)² = 36 O (x-1)2 +(y+2)² + (z–1)² =6 (x-1)? +(y+2)² + (z+1)? = /6

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The standard equation of the sphere that has center (1,-2,1) and passing through the origin, is given by (x+1)2+(y – 2)²+ (z – 1)² =6 Ox +1)2+(y-2)²+ (z – 1)² = 36 O (x-1)2+(y+2)? + (z– 1)² = 6 Ox-1)2+(y+2)° + (z+1)? = /6
Transcribed Image Text:The standard equation of the sphere that has center (1,-2,1) and passing through the origin, is given by (x+1)2+(y – 2)²+ (z – 1)² =6 Ox +1)2+(y-2)²+ (z – 1)² = 36 O (x-1)2+(y+2)? + (z– 1)² = 6 Ox-1)2+(y+2)° + (z+1)? = /6
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To find the standard equation of the sphere that has center 1, -2, 1 and passing through the origin.

 

 

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