The standard enthalpy change for the reaction below is ΔH°rxn = −757 kJ. 3 SF4 (g) + 4 BCl3 (g) → 4 BF3 (g) + 3 SCl2 (l) + 3 Cl2 (g) ΔH°rxn = −757 kJ Substance ΔH°f (kJ/mol) SF4 (g) –775 BCl3 (g) –404 BF3 (g) ? Cl2 (g) 0 SCl2 (l) –50 Use the information provided to calculate the standard enthalpy of formation for BF3 (g). Answer kJ/mol The reaction shown above is Exothermic or Endothermic How many grams of BCl3 (m.w.=117.17 g/mol) must be reacted with excess SF4 in order to produce 6000. kJ of energy? Answer grams
The standard enthalpy change for the reaction below is ΔH°rxn = −757 kJ. 3 SF4 (g) + 4 BCl3 (g) → 4 BF3 (g) + 3 SCl2 (l) + 3 Cl2 (g) ΔH°rxn = −757 kJ Substance ΔH°f (kJ/mol) SF4 (g) –775 BCl3 (g) –404 BF3 (g) ? Cl2 (g) 0 SCl2 (l) –50 Use the information provided to calculate the standard enthalpy of formation for BF3 (g). Answer kJ/mol The reaction shown above is Exothermic or Endothermic How many grams of BCl3 (m.w.=117.17 g/mol) must be reacted with excess SF4 in order to produce 6000. kJ of energy? Answer grams
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The standard enthalpy change for the reaction below is ΔH°rxn = −757 kJ.
3 SF4 (g) + 4 BCl3 (g) → 4 BF3 (g) + 3 SCl2 (l) + 3 Cl2 (g) ΔH°rxn = −757 kJ
|
Substance |
ΔH°f (kJ/mol) |
|
SF4 (g) |
–775 |
|
BCl3 (g) |
–404 |
|
BF3 (g) |
? |
|
Cl2 (g) |
0 |
|
SCl2 (l) |
–50 |
Use the information provided to calculate the standard enthalpy of formation for BF3 (g).
Answer kJ/mol
The reaction shown above is Exothermic or Endothermic
How many grams of BCl3 (m.w.=117.17 g/mol) must be reacted with excess SF4 in order to produce 6000. kJ of energy?
Answer grams
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