The standard deviation of the lengths of hospital stay on the intervention ward is 7.3 days. a. For the variable "length of hospital stay," determine the sampling distribution of the sample mean for samples of 90 patients. The sampling distribution will be approximately normal with mean μ and standard deviation σx=enter your response here days. (Round to four decimal places as needed.) c. Obtain the probability that the sampling error made in estimating the population mean length of stay by the mean length of stay of a sample of 90 patients will be at most 2 days. The probability is approximately enter your response here. (Round to three decimal places as needed.)
The standard deviation of the lengths of hospital stay on the intervention ward is 7.3 days. a. For the variable "length of hospital stay," determine the sampling distribution of the sample mean for samples of 90 patients. The sampling distribution will be approximately normal with mean μ and standard deviation σx=enter your response here days. (Round to four decimal places as needed.) c. Obtain the probability that the sampling error made in estimating the population mean length of stay by the mean length of stay of a sample of 90 patients will be at most 2 days. The probability is approximately enter your response here. (Round to three decimal places as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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The standard deviation of the lengths of hospital stay on the intervention ward is 7.3 days.
a. For the variable "length of hospital stay," determine the sampling distribution of the sample mean for samples of 90 patients.
The sampling distribution will be approximately normal with mean
μ
and standard deviation
σx=enter your response here
days.(Round to four decimal places as needed.)
c. Obtain the probability that the sampling error made in estimating the population mean length of stay by the mean length of stay of a sample of
90 patients will be at most 2 days.
The probability is approximately
enter your response here.
(Round to three decimal places as needed.)
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