The spur gear has a pitch radius of 65 mm (Figure P4.12). During a geartrain's operation, a 900N meshing force acts at 25° relative to horizontal. Determine the moment of that force about the center of the shaft. Use the (a) perpendicular lever arm and (b) moment components methods. Compare the answers of the two methods to verify the accuracy of your work.

The spur gear has a pitch radius of 65 mm (Figure P4.12). During a geartrain's operation, a 900N meshing force acts at 25° relative to horizontal. Determine the moment of that force about the center of the shaft. Use the (a) perpendicular lever arm and (b) moment components methods. Compare the answers of the two methods to verify the accuracy of your work.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

P4.12
The spur gear has a pitch radius of 65 mm (Figure P4.12). During a geartrain's
operation, a 900 N meshing force acts at 25° relative to horizontal. Determine
the moment of that force about the center of the shaft. Use the (a) perpendicular
lever arm and (b) moment components methods. Compare the answers of the
two methods to verify the accuracy of your work.
900 N
25°
65 mm

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For two existing torques, what third force at a given distance from the pivot will balance them? Imagine a meter stick set up as in the figure. It hangs from a central bracket, and two hanging masses can hang from it from each of their brackets. At a third location, a force probe can either pull up or pull down on the stick, depending on what is needed to balance the stick. The mass of the meter stick is 120 g. sketch the situation (drawing r1, r2, r3, F1, F2, and F3) and determine the magnitude (value) and direction (+ or -) of each torque. Don't include the mass of a bracket that would hold the hanging mass in place; assume the mass listed is the entire mass hanging at that point. For each trial, use the principle of equilibrium (where the sum of torques is zero) to calculate the third, unknown force acting at x3
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