The springs of a 1600 kg car compress 4.5 mm when it’s 65 kg driver gets into the seat if the car goes over bump, calculate a) frequency of oscillation b) acceleration of spring compression c) angular frequency
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The springs of a 1600 kg car compress 4.5 mm when it’s 65 kg driver gets into the seat
if the car goes over bump, calculate
a) frequency of oscillation
b) acceleration of spring compression
c) angular frequency
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- A stretched spring is released at time t=0s and allowed to oscillate back and forth on a frictionless surface. The period of harmonic motion is 2s. On the back of this page create the following graphs for one complete oscillation: 1) x-t 2) v-t 3) p-t 4) F,-t 5) a-t 6) K-t 7) U,-t 8) Energy-t Use the space below for any scratch work.5a-A mass on a spring oscillates with an amplitude 0.12 m and a period of 1.0 s. What will be the acceleration of the mass at t = 0.50s? A) 4.7 m/s² B) -4.7 m/s² C) 0.12 m/s² D) 0 m/s?
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- Two people with a combined mass of 127 kg hop into an old car with worn-out shock absorbers. This causes the springs to compress by 9.10 cm. When the car hits a bump in the road, it oscillates up and down with a period of 1.75s. 1)Find the total load supported by the springs M+m=(?)Kg2)Find the mass of the car M=(?)KgIT WAS FOUND WHEN BOBBING FOR APPLES THAT A WHOLE CYCLE FOR BOBBING = 0.7 SECONDS INITIALLY DISPLACED BY IF THE APPLE WAS 10.03m-FIND THE FOLLOWING: GIVEN: PERIOD OF OSCILLATION OF APPLES = 0.1 SECONDS FREQUENCY OF OSCILLATION OF APPLES: 1.428 Hz ANGULAR FREQUENCY = 8.97 rad/s FIND: AMPLITUDE OF POSITION OF APPLE AFTER 5 SECONDS VELOCITY OF APPLE AFTER 5 SECONDS. ACCELERATION OF APPLE AFTER 5 SECONDS OSCILLATION = m m m/s m/s2