The spring in (Figure 1) is compressed by 10 cm. It launches a block across a frictionless surface at 0.50 m/s. The two springs in (Figure 2 ) are identical to the spring of (Eigure 1). They are compressed by the same 10 cm and launch the same block. Figure 10 cm 25 N/m www.1.0 kg Xeq < 1012 > Part A What is the block's speed now? Express your answer with the appropriate units. View Available Hint(s) U₂=0.35 HÅ Submit Previous Answers Provide Feedback m S ? X Incorrect; Try Again; 5 attempts remaining

The spring in (Figure 1) is compressed by 10 cm. It launches a block across a frictionless surface at 0.50 m/s. The two springs in (Figure 2 ) are identical to the spring of (Eigure 1). They are compressed by the same 10 cm and launch the same block. Figure 10 cm 25 N/m www.1.0 kg Xeq < 1012 > Part A What is the block's speed now? Express your answer with the appropriate units. View Available Hint(s) U₂=0.35 HÅ Submit Previous Answers Provide Feedback m S ? X Incorrect; Try Again; 5 attempts remaining

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest. 

Question

Problem 10.21 - Enhanced - with Expanded Hints
The spring in (Figure 1) is compressed by 10 cm. It launches a block
across a frictionless surface at 0.50 m/s. The two springs in (Figure 2
) are identical to the spring of (Figure 1). They are compressed by the
same 10 cm and launch the same block.
Figure
25 N/m
10 cm
1.0 kg
T
Xeq
1 of 2
Part A
What is the block's speed now?
Express your answer with the appropriate units.
► View Available Hint(s)
V₂ = 0.35
Submit
μA
Provide Feedback
1
Previous Answers
m
S
B
?
X Incorrect; Try Again; 5 attempts remaining

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