### Pendulum Motion AnalysisA pendulum is constructed by attaching a 590 g ball to a string 41.0 cm in length. The pendulum is displaced 21.0° from its equilibrium position and then released.#### Part A**Problem:** What is the ball's speed at the lowest point of its trajectory?**Solution:** To find the speed, apply principles of energy conservation, considering both potential and kinetic energy. - Potential energy at the highest point is converted to kinetic energy at the lowest point.**Answer Submission:** - Enter the speed \( v \) in the provided fields with appropriate units.\[ v = \text{Value} \quad \text{Units} \]**Submit your response** after calculating.---#### Part B**Problem:** To what angle does the pendulum swing on the opposite side?**Solution:** Use the conservation of mechanical energy to determine the angle on the opposite swing:- Since energy is conserved, the potential energy on both sides should be equal assuming no energy loss.**Answer Submission:** - Enter the angle \( \theta \) using the provided input fields with appropriate units.\[ \theta = \text{Value} \quad \text{Units} \]**Submit your response** after calculating.For further reading, you may refer to the recommended pages 234 - 238 for a detailed explanation of pendulum motion and energy conservation principles.

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A pendulum is made by tying a 590 g ball to a 41.0 cm -long string. The pendulum is pulled 21.0 ° to one side, then released. Part A You may want to review (Pages 234 - 238). What is the ball's speed at the lowest point of its trajectory? Express your answer with the appropriate units. HẢ ? V = Value Units Submit Request Answer Part B To what angle does the pendulum swing on the other side? Express your answer with the appropriate units. HÀ Value Units Submit Request Answer

A pendulum is made by tying a 590 g ball to a 41.0 cm -long string. The pendulum is pulled 21.0 ° to one side, then released. Part A You may want to review (Pages 234 - 238). What is the ball's speed at the lowest point of its trajectory? Express your answer with the appropriate units. HẢ ? V = Value Units Submit Request Answer Part B To what angle does the pendulum swing on the other side? Express your answer with the appropriate units. HÀ Value Units Submit Request Answer

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter5: Energy

Section: Chapter Questions

Problem 22P: A 60.0-kg athlete leaps straight up into the air from a trampoline with an initial speed of 9.0 m/s....

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Question

### Pendulum Motion Analysis

A pendulum is constructed by attaching a 590 g ball to a string 41.0 cm in length. The pendulum is displaced 21.0° from its equilibrium position and then released.

#### Part A

**Problem:**
What is the ball's speed at the lowest point of its trajectory?

**Solution:**
To find the speed, apply principles of energy conservation, considering both potential and kinetic energy.
- Potential energy at the highest point is converted to kinetic energy at the lowest point.

**Answer Submission:**
- Enter the speed \( v \) in the provided fields with appropriate units.

\[ v = \text{Value} \quad \text{Units} \]

**Submit your response** after calculating.

---

#### Part B

**Problem:**
To what angle does the pendulum swing on the opposite side?

**Solution:**
Use the conservation of mechanical energy to determine the angle on the opposite swing:

- Since energy is conserved, the potential energy on both sides should be equal assuming no energy loss.

**Answer Submission:**
- Enter the angle \( \theta \) using the provided input fields with appropriate units.

\[ \theta = \text{Value} \quad \text{Units} \]

**Submit your response** after calculating.

For further reading, you may refer to the recommended pages 234 - 238 for a detailed explanation of pendulum motion and energy conservation principles.

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