A pendulum is made by tying a 590 g ball to a 41.0 cm -long string. The pendulum is pulled 21.0 ° to one side, then released. Part A You may want to review (Pages 234 - 238). What is the ball's speed at the lowest point of its trajectory? Express your answer with the appropriate units. HẢ ? V = Value Units Submit Request Answer Part B To what angle does the pendulum swing on the other side? Express your answer with the appropriate units. HÀ Value Units Submit Request Answer
A pendulum is made by tying a 590 g ball to a 41.0 cm -long string. The pendulum is pulled 21.0 ° to one side, then released. Part A You may want to review (Pages 234 - 238). What is the ball's speed at the lowest point of its trajectory? Express your answer with the appropriate units. HẢ ? V = Value Units Submit Request Answer Part B To what angle does the pendulum swing on the other side? Express your answer with the appropriate units. HÀ Value Units Submit Request Answer
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter15: Oscillatory Motion
Section: Chapter Questions
Problem 15.5CQ: Figure CQ15.5 shows graphs of the potential energy of four different systems versus the position of...
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![### Pendulum Motion Analysis
A pendulum is constructed by attaching a 590 g ball to a string 41.0 cm in length. The pendulum is displaced 21.0° from its equilibrium position and then released.
#### Part A
**Problem:**
What is the ball's speed at the lowest point of its trajectory?
**Solution:**
To find the speed, apply principles of energy conservation, considering both potential and kinetic energy.
- Potential energy at the highest point is converted to kinetic energy at the lowest point.
**Answer Submission:**
- Enter the speed \( v \) in the provided fields with appropriate units.
\[ v = \text{Value} \quad \text{Units} \]
**Submit your response** after calculating.
---
#### Part B
**Problem:**
To what angle does the pendulum swing on the opposite side?
**Solution:**
Use the conservation of mechanical energy to determine the angle on the opposite swing:
- Since energy is conserved, the potential energy on both sides should be equal assuming no energy loss.
**Answer Submission:**
- Enter the angle \( \theta \) using the provided input fields with appropriate units.
\[ \theta = \text{Value} \quad \text{Units} \]
**Submit your response** after calculating.
For further reading, you may refer to the recommended pages 234 - 238 for a detailed explanation of pendulum motion and energy conservation principles.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3dc90927-a4d4-417e-bb21-8f8d729f068b%2F7f757ea5-80a3-4f12-af35-b7426f54bafb%2Ff6x5itk_processed.png&w=3840&q=75)
Transcribed Image Text:### Pendulum Motion Analysis
A pendulum is constructed by attaching a 590 g ball to a string 41.0 cm in length. The pendulum is displaced 21.0° from its equilibrium position and then released.
#### Part A
**Problem:**
What is the ball's speed at the lowest point of its trajectory?
**Solution:**
To find the speed, apply principles of energy conservation, considering both potential and kinetic energy.
- Potential energy at the highest point is converted to kinetic energy at the lowest point.
**Answer Submission:**
- Enter the speed \( v \) in the provided fields with appropriate units.
\[ v = \text{Value} \quad \text{Units} \]
**Submit your response** after calculating.
---
#### Part B
**Problem:**
To what angle does the pendulum swing on the opposite side?
**Solution:**
Use the conservation of mechanical energy to determine the angle on the opposite swing:
- Since energy is conserved, the potential energy on both sides should be equal assuming no energy loss.
**Answer Submission:**
- Enter the angle \( \theta \) using the provided input fields with appropriate units.
\[ \theta = \text{Value} \quad \text{Units} \]
**Submit your response** after calculating.
For further reading, you may refer to the recommended pages 234 - 238 for a detailed explanation of pendulum motion and energy conservation principles.
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