The spring has a stiffness of k = 800 N/m and an unstretched length of 200 mm. Determine the force in cables BC and BD when the spring is held in the position shown. A k = 800 N/m www -500 mm -400 mm- D 400 mm 300 mm

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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### Determining Forces in Cables BC and BD with a Spring System

**Problem Statement:**
The spring has a stiffness of \( k = 800 \, \text{N/m} \) and an unstretched length of 200 mm. Determine the force in cables BC and BD when the spring is held in the position shown.

**Given Data:**
- Stiffness of spring \( k = 800 \, \text{N/m} \)
- Unstretched length of spring: 200 mm
- Horizontal distance from point A to point B: 500 mm (AB)
- Distance from point B to the wall along the horizontal direction: 400 mm (BC)
- Vertical distance from point C to point B: 400 mm (BC)
- Vertical distance from point D to point B: 300 mm (BD)

**Diagram Description:**
The illustration shows a spring connected between points A and B. The spring has a noted stiffness of 800 N/m. Point B is connected to two cables, BC and BD, which support it vertically.

- Point A is fixed to the left boundary.
- The spring is extended to point B on the horizontal, which is 500 mm from A.
- Point B is vertically supported by cable BC extending 400 mm upwards to point C, and cable BD extending 300 mm downwards to point D.

### Steps to Solve:
1. **Calculate the extended length of the spring AB:**
    Use the given coordinates to find the actual length of AB using the Pythagorean Theorem.

2. **Determine the elongation of the spring:**
    \[
    \Delta L = L_{AB} - L_0
    \]
    where \( L_0 \) is the original length (200 mm).

3. **Find the force in the spring from Hooke's Law:**
    \[
    F = k \Delta L
    \]
   
4. **Resolve forces in horizontal and vertical directions:**
    The forces in cables BC and BD need to be found by analyzing the equilibrium of forces at point B.

5. **Set up equilibrium equations:**
    \[
    \sum F_x = 0 \quad \text{(horizontal equilibrium)}
    \]
    \[
    \sum F_y = 0 \quad \text{(vertical equilibrium)}
    \]

### Solution:
Following these steps involves detailed calculations of trigon
Transcribed Image Text:### Determining Forces in Cables BC and BD with a Spring System **Problem Statement:** The spring has a stiffness of \( k = 800 \, \text{N/m} \) and an unstretched length of 200 mm. Determine the force in cables BC and BD when the spring is held in the position shown. **Given Data:** - Stiffness of spring \( k = 800 \, \text{N/m} \) - Unstretched length of spring: 200 mm - Horizontal distance from point A to point B: 500 mm (AB) - Distance from point B to the wall along the horizontal direction: 400 mm (BC) - Vertical distance from point C to point B: 400 mm (BC) - Vertical distance from point D to point B: 300 mm (BD) **Diagram Description:** The illustration shows a spring connected between points A and B. The spring has a noted stiffness of 800 N/m. Point B is connected to two cables, BC and BD, which support it vertically. - Point A is fixed to the left boundary. - The spring is extended to point B on the horizontal, which is 500 mm from A. - Point B is vertically supported by cable BC extending 400 mm upwards to point C, and cable BD extending 300 mm downwards to point D. ### Steps to Solve: 1. **Calculate the extended length of the spring AB:** Use the given coordinates to find the actual length of AB using the Pythagorean Theorem. 2. **Determine the elongation of the spring:** \[ \Delta L = L_{AB} - L_0 \] where \( L_0 \) is the original length (200 mm). 3. **Find the force in the spring from Hooke's Law:** \[ F = k \Delta L \] 4. **Resolve forces in horizontal and vertical directions:** The forces in cables BC and BD need to be found by analyzing the equilibrium of forces at point B. 5. **Set up equilibrium equations:** \[ \sum F_x = 0 \quad \text{(horizontal equilibrium)} \] \[ \sum F_y = 0 \quad \text{(vertical equilibrium)} \] ### Solution: Following these steps involves detailed calculations of trigon
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