The specific heat of a certain type of cooking oil is 0.418 cal/(g-°C). How much heat energy is needed to raise the temperature of 0.515 kg of this oil from 23.0 °C to 60.0 °C? q = cal

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**Question:**

The specific heat of a certain type of cooking oil is 0.418 cal/(g·°C). How much heat energy is needed to raise the temperature of 0.515 kg of this oil from 23.0 °C to 60.0 °C?

**Answer Box:**

q = _______ cal

**Tools:**

- Option to multiply the calculated result by a power of ten (x10^y).

**Explanation:**

This problem involves calculating the heat energy (q) required to change the temperature of a given mass of cooking oil using the formula:

\[ 
q = m \cdot c \cdot \Delta T 
\]

Where:
- \( m \) is the mass of the oil (0.515 kg or 515 g),
- \( c \) is the specific heat capacity (0.418 cal/g·°C),
- \( \Delta T \) is the change in temperature (60.0 °C - 23.0 °C = 37.0 °C).

To find the energy in calories, substitute these values into the formula.
Transcribed Image Text:**Question:** The specific heat of a certain type of cooking oil is 0.418 cal/(g·°C). How much heat energy is needed to raise the temperature of 0.515 kg of this oil from 23.0 °C to 60.0 °C? **Answer Box:** q = _______ cal **Tools:** - Option to multiply the calculated result by a power of ten (x10^y). **Explanation:** This problem involves calculating the heat energy (q) required to change the temperature of a given mass of cooking oil using the formula: \[ q = m \cdot c \cdot \Delta T \] Where: - \( m \) is the mass of the oil (0.515 kg or 515 g), - \( c \) is the specific heat capacity (0.418 cal/g·°C), - \( \Delta T \) is the change in temperature (60.0 °C - 23.0 °C = 37.0 °C). To find the energy in calories, substitute these values into the formula.
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