The specific heat of a certain type of cooking oil is 1.75 J/(g.°C). How much heat energy is needed to raise the temperature of 2.14 kg of this oil from 23 °C to 191 °C? q = J
The specific heat of a certain type of cooking oil is 1.75 J/(g.°C). How much heat energy is needed to raise the temperature of 2.14 kg of this oil from 23 °C to 191 °C? q = J
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
![The specific heat of a certain type of cooking oil is 1.75 J/(g·°C). How much heat energy is needed to raise the temperature of 2.14 kg of this oil from 23 °C to 191 °C?
\[ q = \; \]
\[\mathrm{J}\]
Explanation:
This is a heat energy calculation problem. To find the heat energy (\( q \)), you can use the formula:
\[ q = m \times c \times \Delta T \]
Where:
- \( m \) is the mass of the substance in grams (convert 2.14 kg to grams: 2.14 kg = 2140 g).
- \( c \) is the specific heat capacity (1.75 J/(g·°C)).
- \( \Delta T \) is the change in temperature (191 °C - 23 °C = 168 °C).
Substitute the values into the formula to calculate the heat energy required.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1cab08ae-8e5c-4fa2-a89b-725536e38ab3%2Fe8db9d00-deae-475e-8912-9291f6332e68%2F8ichmw9_processed.png&w=3840&q=75)
Transcribed Image Text:The specific heat of a certain type of cooking oil is 1.75 J/(g·°C). How much heat energy is needed to raise the temperature of 2.14 kg of this oil from 23 °C to 191 °C?
\[ q = \; \]
\[\mathrm{J}\]
Explanation:
This is a heat energy calculation problem. To find the heat energy (\( q \)), you can use the formula:
\[ q = m \times c \times \Delta T \]
Where:
- \( m \) is the mass of the substance in grams (convert 2.14 kg to grams: 2.14 kg = 2140 g).
- \( c \) is the specific heat capacity (1.75 J/(g·°C)).
- \( \Delta T \) is the change in temperature (191 °C - 23 °C = 168 °C).
Substitute the values into the formula to calculate the heat energy required.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
Recommended textbooks for you
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY