The solution to (2x – 4y – 3)dy = (x – 2y)dx is: %3D а. 6у—х? — 4ху + 4y? %3D с c. 6y +x? + 4xy+ 4y? = c b. 6y +x? – 4xy – 4y2 = c d. by+x? -4ху + 4y? %3D с
The solution to (2x – 4y – 3)dy = (x – 2y)dx is: %3D а. 6у—х? — 4ху + 4y? %3D с c. 6y +x? + 4xy+ 4y? = c b. 6y +x? – 4xy – 4y2 = c d. by+x? -4ху + 4y? %3D с
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:The solution to (2х- 4у - 3)dy %3 (х - 2у)dx is:
с. 6у +x? +4ху + 4y? —с
d. 6y+x* - 4ху + 4y* %3D с
а. бу-х? - 4ху + 4y? — с
b. bу+x? -4ху - 4y? %3D с
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