The solution to (2х- 4у - 3)dy %3 (х - 2у)dx is:с. 6у +x? +4ху + 4y? —сd. 6y+x* - 4ху + 4y* %3D са. бу-х? - 4ху + 4y? — сb. bу+x? -4ху - 4y? %3D с

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Answered: The solution to (2x – 4y – 3)dy = (x –…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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3x + 5y = 4 4 --X- 3 (х, у) %3 1. %3D
Susie was asked to solve the following system of equations: x+ 3y = 1 -3х-Зу -- 1 Her solution steps and final answer are below, but her final answer is not correctl Identify where she made her mistake(s), and then solve the problem correctly. Include each of your solution steps and the final answer. A x= 3y + 1 В. 3(3у + 1) - 3у - C. - 9y- 3-3y= -1 D. - 12y = -4 y = E. F. ***-1 G x +1= 1 H. x= 2 Answer: (2. Use the nanerclin hutton helow to attach files re to search
The cost(c) of transmitting electric power partly varies as the cube of the distance(d)and partly varies inversely as the temperature(t) in which the power is illuminated. When the distance is 5miles at temperature 15`c the cost is GHc1,010 and when distance is 10miles at temperature 25`c the cost is GHc8,006.Find an equation connecting c,d,t. Find the cost of transmission when distance is 40miles and temperature of 30`c
Which line passes through the point (4, -7) and is perpendicular to the line x-4y = 8? %3D 1 A. y =--x-11 C. y =--x-6 B. y = -4x- 23 D. y =-4x +9
Find đ · b for å = (4,1, ) and b = (6,–3,-8).
1. 5x + 3 = 7x - 1. Find x а. 1/3 b. 2 С. 1 d. 2 2. 5x + 2(x + 7) = 14x - 7. Find x а. 1 b. 2 с. 3 d. 4
The coordinates of the missing point are А. (4, 4) В. (5,4) (-1,4) (?, ?) С. (6, 4) D. (7, 4)
Which set of coordinates follows these two rules? • X-coordinate: Start with 4 and add 4 to each term. • y-coordinate: Start with 4 and multiply each term by 2. @ (4, 4), (8, 8), (12, 16) ® (4, 4), (8, 8), (16, 16) ©(4, 4), (6, 16), (8, 64) O (4, 4), (8, 6), (12, 8)
-5x y"+ 3y - 10y = - 1l4 ye
Express y in terms of x in the second equation. |-4x +9y - 2 = 0 y + 3 3x - 2 y = 2 1. 4. = -X 10x +y = 12 6 (5x - 7y = 2 2. [3 (x + y) = 2x - 4 5. %3D |12x + 2y - 2 = 0 12 (x + у) - 3 в Зх + у - 1 5 X +- V= 3. 3 X - -INin
Express in terms of i. 1. V - 100
justify each step 15y + 7 = 12 -20y = 12 35y + 7 = 12 35y = 5 y= 1/7

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The solution to (2x – 4y – 3)dy = (x – 2y)dx is: %3D а. 6у—х? — 4ху + 4y? %3D с c. 6y +x? + 4xy+ 4y? = c b. 6y +x? – 4xy – 4y2 = c d. by+x? -4ху + 4y? %3D с