Solve by the substitution method: Sy = 2x – 3 1 4х — Зу %3D 5. Substitute 2x - 3 for y in the second equation. 4х — 3(2х — 3) 3D 5 4х — бх + 9 3D5 -2x + 9 = 5 -2x = -4 x = 2 Find y. Substitute 2 for x in y = 2x – 3. y = 2(2) – 3 = 4 – 3 = 1 The ordered pair (2, 1) checks. The solution is (2,1) and {(2, 1)} is the solution set.

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