The solubility product for Ca3(PO4)2 is written as OK-CA-PO-1 C₂3(PO4)₂ 30 [PO] OK - [Ca²+]³[PO³-]² Ksp - K= 3 [Ca] 2[PO] [Ca, (PO4)₂] Ox-3[Ca] [PO] = [Ca²+]³[PO³-]² K=[Ca,(PO)₂] 2

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Q: The fictitious complex M(SCN)2 can be produced from an aqueous equilibrium in which the M2+ ion is…

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Q: Initial Concentration 9.091x10-4 1.818x10-4 0 Change in Concentration       Equilibrium…

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