The Solubility Product Constant for silver hydroxide is 2.0 × 10-8. The molar solubility of silver hydroxide in a 0.193 M silver acetate solution is M.

World of Chemistry, 3rd edition
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Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
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Chapter17: Equilibrium
Section: Chapter Questions
Problem 52A
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**Using References to Determine Solubility**

To solve the problem of finding the molar solubility of silver hydroxide in a 0.193 M silver acetate solution, it is necessary to use the Solubility Product Constant (Ksp). 

**Given:**
- **Solubility Product Constant (Ksp) for silver hydroxide, AgOH**: \(2.0 \times 10^{-8}\)

**Problem:**
Calculate the molar solubility of silver hydroxide in a 0.193 M silver acetate solution.

**Explanation:**
Silver hydroxide (AgOH) will dissolve in the silver acetate solution up to the point where the product of the concentrations of the ions equals the \( K_{sp} \). Typically, understanding how common ion effect reduces solubility in such a solution is key. 

Fill in the value of the calculated molar solubility in the given space.
Transcribed Image Text:**Using References to Determine Solubility** To solve the problem of finding the molar solubility of silver hydroxide in a 0.193 M silver acetate solution, it is necessary to use the Solubility Product Constant (Ksp). **Given:** - **Solubility Product Constant (Ksp) for silver hydroxide, AgOH**: \(2.0 \times 10^{-8}\) **Problem:** Calculate the molar solubility of silver hydroxide in a 0.193 M silver acetate solution. **Explanation:** Silver hydroxide (AgOH) will dissolve in the silver acetate solution up to the point where the product of the concentrations of the ions equals the \( K_{sp} \). Typically, understanding how common ion effect reduces solubility in such a solution is key. Fill in the value of the calculated molar solubility in the given space.
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