O 3.0 x 10 -12The solubility of Bi2S3 was found experimentally to be 1.0 x 10 15Calculate the value for Ksp-mol per liter.3+(aq)3s2 (aq)Bi2S3e 2BiO 8.9 x 10 -44O 1.6 x 10 -8O 6. 8 x 10 -23O 7.5 x 10 -18O 1.1 x 10 -73O 3.9 x 10 -5O 1.5 x 10 -6

The molar solubility of Bi2S3 =s =1.0 x 10-15 mol/L Bi2S3 ⇌ 2 Bi3+ + 3S2- 2s…

The solubility of Bi2S3 was found experimentally to be 1.0 x 1015 Calculate the value for Ksp. mol per liter. 3+(aq) Bi2S3 2Bi 3s2 (aq) 3.0 x 10 -12 O 8.9 x 10 -44 O 1.6 x 10 -8 O 6. 8 x 10 -23 O 7.5 x 10-18 O 1.1 x 10-73 O 3.9 x 10 -5 O 1.5 x 10 -6

The solubility of Bi2S3 was found experimentally to be 1.0 x 1015 Calculate the value for Ksp. mol per liter. 3+(aq) Bi2S3 2Bi 3s2 (aq) 3.0 x 10 -12 O 8.9 x 10 -44 O 1.6 x 10 -8 O 6. 8 x 10 -23 O 7.5 x 10-18 O 1.1 x 10-73 O 3.9 x 10 -5 O 1.5 x 10 -6

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

O 3.0 x 10 -12
The solubility of Bi2S3 was found experimentally to be 1.0 x 10 15
Calculate the value for Ksp-
mol per liter.
3+(aq)
3s2 (aq)
Bi2S3
e 2Bi
O 8.9 x 10 -44
O 1.6 x 10 -8
O 6. 8 x 10 -23
O 7.5 x 10 -18
O 1.1 x 10 -73
O 3.9 x 10 -5
O 1.5 x 10 -6

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Acetic acid: ka= 1.75x10s Ammonia: ko = 1.8x10s Hydrofluoric acid: 7.2 x10+ Hydrogen sulfide: kai = 5.7x10+ kaz = 1.2x10-15 Solubility Product Constants, km Nickel hydroxide 2.0x1014 Nickel sulfide: 1.4x1024 Manganous 4.5 x1014 Manganous sulfide: 1.4x1015 hydroxide: Aluminum chromium 1.0x1030 hydroxide: 1.9x10 hydroxide: 2. A 200 ml of 0.0S F hydrogen sulfide solution is added to 25 ml 1.5 Facetic acid solution. Compute the sulfide ion concentration of the solution.