Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![The solubility of Ag₂SO₄ is measured and found to be 4.95 g/L. Use this information to calculate a Ksp value for silver sulfate.
Ksp = [ ]
---
To solve the problem, consider the dissociation equation of silver sulfate (Ag₂SO₄) in water:
Ag₂SO₄ ⇌ 2Ag⁺ + SO₄²⁻
1. **Calculate Molar Solubility:**
- Molar mass of Ag₂SO₄ = (2×107.87) + 32.07 + (4×16.00) = 311.87 g/mol.
- Molar solubility = 4.95 g/L ÷ 311.87 g/mol ≈ 0.0159 mol/L.
2. **Set Up Equilibrium Concentration:**
- [Ag⁺] = 2 × 0.0159 mol/L = 0.0318 mol/L
- [SO₄²⁻] = 0.0159 mol/L
3. **Calculate Ksp:**
- Ksp = [Ag⁺]² × [SO₄²⁻] = (0.0318)² × 0.0159
- Ksp ≈ 1.61 × 10⁻⁵
Hence, the Ksp value for silver sulfate is approximately 1.61 × 10⁻⁵.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d65d074-1570-4831-8dec-170f6bb6e3ab%2F78c05f05-ece4-492c-bc07-99fbf0ab321b%2Fzvrn7au_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The solubility of Ag₂SO₄ is measured and found to be 4.95 g/L. Use this information to calculate a Ksp value for silver sulfate.
Ksp = [ ]
---
To solve the problem, consider the dissociation equation of silver sulfate (Ag₂SO₄) in water:
Ag₂SO₄ ⇌ 2Ag⁺ + SO₄²⁻
1. **Calculate Molar Solubility:**
- Molar mass of Ag₂SO₄ = (2×107.87) + 32.07 + (4×16.00) = 311.87 g/mol.
- Molar solubility = 4.95 g/L ÷ 311.87 g/mol ≈ 0.0159 mol/L.
2. **Set Up Equilibrium Concentration:**
- [Ag⁺] = 2 × 0.0159 mol/L = 0.0318 mol/L
- [SO₄²⁻] = 0.0159 mol/L
3. **Calculate Ksp:**
- Ksp = [Ag⁺]² × [SO₄²⁻] = (0.0318)² × 0.0159
- Ksp ≈ 1.61 × 10⁻⁵
Hence, the Ksp value for silver sulfate is approximately 1.61 × 10⁻⁵.
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