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The complex ion Cu(NH3)2* is formed from a solution that initially contains 1.50 x 10-3 M CUNO3 and 0.085 M NH3. Cu (aq) + 2 NH3(aq) = Cu(NH3)2*(aq) Kf=6.3x10-12 Determine the concentration of free Cut that remains in solution under these conditions. O 4.0 M 3.5 x 10-12 M 6.3 x 10-12 M 2.5,M

The complex ion Cu(NH3)2* is formed from a solution that initially contains 1.50 x 10-3 M CUNO3 and 0.085 M NH3. Cu (aq) + 2 NH3(aq) = Cu(NH3)2*(aq) Kf=6.3x10-12 Determine the concentration of free Cut that remains in solution under these conditions. O 4.0 M 3.5 x 10-12 M 6.3 x 10-12 M 2.5,M

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The complex ion Cu(NH3)2* is formed from a solution that initially contains 1.50 x 10-3 M CUNO3 and 0.085 M NH3. Cut (aq) + 2 NH3(aq) = Cu(NH3)2 (aq) 1 Kf =6.3 x 10-12 Determine the concentration of free Cut that remains in solution under these conditions. O 4.0 M 3.5 x 10-12 M 6.3 x 10-12 M 2.5.M
Transcribed Image Text:The complex ion Cu(NH3)2* is formed from a solution that initially contains 1.50 x 10-3 M CUNO3 and 0.085 M NH3. Cut (aq) + 2 NH3(aq) = Cu(NH3)2 (aq) 1 Kf =6.3 x 10-12 Determine the concentration of free Cut that remains in solution under these conditions. O 4.0 M 3.5 x 10-12 M 6.3 x 10-12 M 2.5.M
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