The solubility of a hypothetical salt (A2B) is 0.095 g/100. mL at 25°C (hint: element A is in group 1A while element B is in group 6A). What is the value of the solubility product constant? The molar mass of this salt is 250.0 g/mol.
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Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
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![**Question 3: Solubility and Solubility Product Constant Calculation**
The solubility of a hypothetical salt \( \text{A}_2\text{B} \) is 0.095 g/100 mL at 25°C. (Hint: Element A is in group 1A while element B is in group 6A.) What is the value of the solubility product constant? The molar mass of this salt is 250.0 g/mol.
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**Explanation for Educational Context:**
This question involves calculating the solubility product constant (\( K_{sp} \)) for the salt \( \text{A}_2\text{B} \). Here's how you approach it:
1. **Determine Molar Solubility**:
- Find the molarity of the dissolved salt using its solubility in grams per 100 mL and its molar mass.
2. **Write the Dissociation Equation**:
- The salt \( \text{A}_2\text{B} \) dissociates into 2A\(^+\) and B\(^{2-}\) ions.
3. **Calculate Ion Concentrations**:
- Use the stoichiometry of the dissociation reaction to find the molar concentrations of the ions in solution.
4. **Calculate \( K_{sp} \)**:
- Use the ion concentrations to compute the \( K_{sp} \) using the expression: \( K_{sp} = [A^+]^2[B^{2-}] \).
This exercise helps students understand solubility, stoichiometry, and equilibrium concepts related to inorganic salts.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F485c3033-fba7-4e27-bc3f-5d79c440a1f8%2F2d59b609-ecdc-463f-aa29-fcafdef7364f%2Fjc9in3y6_processed.jpeg&w=3840&q=75)
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