The sliding glass door rolls on the two small lower wheels A and B. Under normal conditions the upper wheels do not touch their horizontal guide. (a) Compute the force P required to slide the door at a steady speed if wheel A becomes "frozen" and does not turn in its bearing. (b) Rework the problem if wheel B becomes frozen instead of wheel A. The coefficient of kinetic friction between a frozen wheel and the supporting surface is 0.35, and the center of mass of the 101-lb door is at its geometric center. Neglect the small diameter of the wheels. 38" 38" A 25" 7" 7"

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The sliding glass door rolls on the two small lower wheels A and B. Under normal conditions the upper wheels do not touch their
horizontal guide. (a) Compute the force P required to slide the door at a steady speed if wheel A becomes "frozen" and does not turn in
its bearing. (b) Rework the problem if wheel B becomes frozen instead of wheel A. The coefficient of kinetic friction between a frozen
wheel and the supporting surface is 0.35, and the center of mass of the 101-lb door is at its geometric center. Neglect the small
diameter of the wheels.
38"
38"
A
25"
7"
'7"
Answer:
(a) P =
i
Ib
(b) P =
i
Ib
Transcribed Image Text:The sliding glass door rolls on the two small lower wheels A and B. Under normal conditions the upper wheels do not touch their horizontal guide. (a) Compute the force P required to slide the door at a steady speed if wheel A becomes "frozen" and does not turn in its bearing. (b) Rework the problem if wheel B becomes frozen instead of wheel A. The coefficient of kinetic friction between a frozen wheel and the supporting surface is 0.35, and the center of mass of the 101-lb door is at its geometric center. Neglect the small diameter of the wheels. 38" 38" A 25" 7" '7" Answer: (a) P = i Ib (b) P = i Ib
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