(part 1 of 2) A merry-go-round rotates at the rate of 0.12 rev/s with an 83 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 63 kg cylinder of radius of 1.5 m. Answer in units of rad/s. (part 2 of 2) What is the change in kinetic energy due to this movement? Answer in units of J.
(part 1 of 2) A merry-go-round rotates at the rate of 0.12 rev/s with an 83 kg man standing at a point 1.5 m from the axis of rotation. What is the new angular speed when the man walks to a point 0 m from the center? Consider the merry-go-round is a solid 63 kg cylinder of radius of 1.5 m. Answer in units of rad/s. (part 2 of 2) What is the change in kinetic energy due to this movement? Answer in units of J.
Related questions
Question

Transcribed Image Text:(part 1 of 2)
A merry-go-round rotates at the rate of
0.12 rev/s with an 83 kg man standing at
a point 1.5 m from the axis of rotation.
What is the new angular speed when the
man walks to a point 0 m from the center?
Consider the merry-go-round is a solid 63 kg
cylinder of radius of 1.5 m.
Answer in units of rad/s.
(part 2 of 2)
What is the change in kinetic energy due to
this movement?
Answer in units of J.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 4 images
