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The simply supported beam consists of a W410 × 85 structural steel wide-flange shape [E = 200 GPa; 1 = 316 x 106 mm4]. For the loading shown, use discontinuity functions to compute: (a) the slope of the beam at A, and A (b) the deflection Vmid of the beam at midspan. Assume LAB LCD = 2.7 m, LBC = 3.9 m, w = 75 kN/m.

The simply supported beam consists of a W410 × 85 structural steel wide-flange shape [E = 200 GPa; 1 = 316 x 106 mm4]. For the loading shown, use discontinuity functions to compute: (a) the slope of the beam at A, and A (b) the deflection Vmid of the beam at midspan. Assume LAB LCD = 2.7 m, LBC = 3.9 m, w = 75 kN/m.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The simply supported beam consists of a W410 × 85 structural steel wide-flange shape [E = 200 GPa; 1 = 316 x 106 mm4]. For the loading shown, use discontinuity functions to compute: (a) the slope of the beam at A, and A (b) the deflection Vmid of the beam at midspan. Assume LAB = LCD = 2.7 m, Lgc = 3.9 m, w = 75 kN/m. W LAB B LBC с W LCD D
Transcribed Image Text:The simply supported beam consists of a W410 × 85 structural steel wide-flange shape [E = 200 GPa; 1 = 316 x 106 mm4]. For the loading shown, use discontinuity functions to compute: (a) the slope of the beam at A, and A (b) the deflection Vmid of the beam at midspan. Assume LAB = LCD = 2.7 m, Lgc = 3.9 m, w = 75 kN/m. W LAB B LBC с W LCD D
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When I put it in the answer was incorrect. When calculating Ra shouldn't it be Ra = -2.7(75)-2.7(75) because there are two w's. Also why does the FBD look like that?

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