The simply supported beam AB as shown in Figure Q3(a) has a uniform load of intensity, w=15 kN/m acts throughout the entire length of the beam. The cross-section of the beam is shown in Figure Q3(b). Given the second moment of area, INA = 36 x 106 mm“. (a) Determine the shear stress at the top of the hole at section a-a. (b) Determine the maximum shear stress at point M and N based on the maximum shear force. (c) Calculate the absolute maximum shear stress of the beam. 0.6 m 1.8 m a w = 15 kN/m В Figure Q3 (a) 160 Ø30 hole 110 NA * 70 M y = 80 40 N 100 All dimensions in mm

Structural Analysis
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Chapter2: Loads On Structures
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The simply supported beam AB as shown in Figure Q3(a) has a uniform load of intensity,
w=15 kN/m acts throughout the entire length of the beam. The cross-section of the beam is
shown in Figure Q3(b). Given the second moment of area, INA = 36 x 106 mm“.
(a) Determine the shear stress at the top of the hole at section a-a.
(b) Determine the maximum shear stress at point M and N based on the maximum shear
force.
(c) Calculate the absolute maximum shear stress of the beam.
0.6 m
1.8 m
a.
w = 15 kN/m
В
Figure Q3 (a)
160
Ø30 hole
110
NA *
70
M
y = 80
40
N
100
All dimensions in mm
Transcribed Image Text:The simply supported beam AB as shown in Figure Q3(a) has a uniform load of intensity, w=15 kN/m acts throughout the entire length of the beam. The cross-section of the beam is shown in Figure Q3(b). Given the second moment of area, INA = 36 x 106 mm“. (a) Determine the shear stress at the top of the hole at section a-a. (b) Determine the maximum shear stress at point M and N based on the maximum shear force. (c) Calculate the absolute maximum shear stress of the beam. 0.6 m 1.8 m a. w = 15 kN/m В Figure Q3 (a) 160 Ø30 hole 110 NA * 70 M y = 80 40 N 100 All dimensions in mm
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