The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 367 389 375 377 384 388 409 362 358 415 Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤ 400). [Hint: P(X ≤ 400) = ((400 -μ)/o).] (Round your answer to four decimal places.)
The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 367 389 375 377 384 388 409 362 358 415 Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤ 400). [Hint: P(X ≤ 400) = ((400 -μ)/o).] (Round your answer to four decimal places.)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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![The shear strength of each of ten test spot welds is determined, yielding the following data (psi):
375 377 384 388 409 362 358 415
367 389
Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤400). [Hint: P(X ≤400) = ((400 -μ)/o).] (Round your answer to four decimal
places.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F223b9866-d226-4984-967c-d26b057ee9a7%2F347886e1-f6b5-46f6-9292-fc00d7e29755%2Fwehznw_processed.png&w=3840&q=75)
Transcribed Image Text:The shear strength of each of ten test spot welds is determined, yielding the following data (psi):
375 377 384 388 409 362 358 415
367 389
Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤400). [Hint: P(X ≤400) = ((400 -μ)/o).] (Round your answer to four decimal
places.)
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