The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 389 367 378 375 400 362 358 409 380 415 Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle P(X ≤ 400). [Hint: P(X ≤ 400) = ((400-μ)/o).] (Round your answer to four decimal places.)

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
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The shear strength of each of ten test spot welds is determined, yielding the following data (psi):
389 367 378 375 400 362
358 409 380 415
Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of
P(X ≤ 400). [Hint: P(X ≤ 400) = ((400 μ)/o).] (Round your answer to four decimal places.)
You may need to use the appropriate table in the Appendix of Tables to answer this question.
Transcribed Image Text:The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 389 367 378 375 400 362 358 409 380 415 Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤ 400). [Hint: P(X ≤ 400) = ((400 μ)/o).] (Round your answer to four decimal places.) You may need to use the appropriate table in the Appendix of Tables to answer this question.
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