The shaft of a pump starts from rest and has an angular acceleration of 3.00 rad/s² for 18.0 s. at the end of this interval, what is (a) the shaft's angular speed and (b) the angle through which the shaft has turned?
Angular speed, acceleration and displacement
Angular acceleration is defined as the rate of change in angular velocity with respect to time. It has both magnitude and direction. So, it is a vector quantity.
Angular Position
Before diving into angular position, one should understand the basics of position and its importance along with usage in day-to-day life. When one talks of position, it’s always relative with respect to some other object. For example, position of earth with respect to sun, position of school with respect to house, etc. Angular position is the rotational analogue of linear position.
I need help with this physics problem please help me
Initially the shaft is at rest i.e. initial angular speed .
angular acceleration
at the end of this interval
a) angular speed of shaft
using equation
we get
Hence shaft's angular speed after time interval = 54 rad/s.
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