The Set API has the following methods: void add(T) boolean contains(T) boolean remove(T) The data structure to use for best worst case performance for time complexity, with answers always guaranteed to be correct
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The Set<T> API has the following methods:
void add(T)
boolean contains(T)
boolean remove(T)
The data structure to use for best worst case performance for time complexity, with answers always guaranteed to be correct
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- NOTE: WRITE IN C# Write a distributed probability random number generator using one of the probability sampling methods (like rejection sampling). Explain the codes and the sampling implementation in detail. Example: İnputs : (3, 0.4) (5, 0.5) Output: Generated random number is 3, it has %40 probability Generated random number is 5, it has %50 probability NOTE: WRITE IN C# NOTE: MAKE A GENERIC SOLUTION THAT APPLIES FOR ANY GIVEN NUMBER AND PROBABILITY. NOT JUST BASED ON THIS EXAMPLE !!!A spell checker in a word processing program makes suggestions when it finds a word not in the dictionary. To determine what words to suggest, it tries to find similar words. One measure of word similarity is the Levenshtein distance, which measures the number of substitutions, additions, or deletions that are required to change one word into another. For example, the words spit and spot are a distance of 1 apart; changing spit to spot requires one substitution (i for o). Likewise, spit is distance 1 from pit since the change requires one deletion (the s). The word spite is also distance 1 from spit since it requires one addition (the e). The word soot is distance 2 from spit since two substitutions would be required. a. Create a graph using words as vertices, and edges connecting words with a Levenshtein distance of 1. Use the misspelled word “moke” as the center, and try to find at least 10 connected dictionary words. How might a spell checker use this graph? b. Improve the method…SOLVE IN PYTHON A bracket is considered to be any one of the following characters: (, ), {, }, [, or ]. Two brackets are considered to be a matched pair if the an opening bracket (i.e., (, [, or {) occurs to the left of a closing bracket (i.e., ), ], or }) of the exact same type. There are three types of matched pairs of brackets: [],{},and ().A matching pair of brackets is not balanced if the set of brackets it encloses are not matched. For example, {[(])} is not balanced because the contents in between { and } are not balanced. Write a program that take string of bracket pairs from user and reply Yes or No after evaluate. Your program should working like This.{[()]} Yes{[(])} No{{[[(())]]}} Yes
- int functionC (int n) { int i, j, sumC = 0; for (i=n; i > 0; i=i-5) for (j=1; j 0) { if (functionC(n) % 2 == 0) { for (i=m; i > 0; i=i/3) sumE++; } else (10) Asymptotic runtime of functionE { for (i=m; i > 0; i=i-3) sumE--; } n--; } return sumE;Calculate the expected time for the followingtasks.Bum 0; for (int i = 1; iTest the program using the following procedure (Use Linked List): Call PUSH(5) Call PUSH(2) Call PUSH(3) Call POP() Call PUSH(6) Call PUSH(9) Call PUSH(3) Call DISPLAY() Call TOP() Note: solve as soon as possible use c++ languagedef problem_a(n) sum=0 k=n while k>0: for i in range(k): sum +=1 k=k//2 return sum what will be its running time ? Please explainFind the recurrence relation of the code below and find the runtime analysis of it using any method. function mult(a, b) if b = 0: return 0 else if b is odd: return (mult(2a,[b/2 )+a) else: return (mult(2a, [b/2 ))Match expression (exprN) with code! expr1for (; expr2; expr3) expr4 expr1: Answer 1expr2: Answer 2expr3: Answer 3expr4: Answer 4 Select from : i=0; While void {sats} i <20; codline 1, codeline 2, codeline3 i ++function result = result = ''; 1 tokens_to_str_code(token_mat, time_unit) 3 for i =1:size(token_mat,1) 4 5 if(token_mat (i,1) if(token_mat(i,2) > 4*time_unit) result = strcat(result,"-"); elseif((token_mat(i,2) > time_unit) && (token_mat(i,2) 8*time_unit) result = strcat(result,"/"); elseif((token_mat(i,2) 11 == 0) 12 13 14 4*time_unit) && (token_mat(i,2) < 8*time_unit)) 15 result strcat(result," "); %3D 16 end 17 end 18 end 19 end 20 21 Check Test Expected Got tokens %3D [1 4; е 3; 1 3; е 1; 1 3; е 1; 1 1; ө 1; 1 1 ]; time_unit = .5; disp( tokens_to_str_code( tokens, time_unit )) tokens = [ 0 4; 1 1457; 0 463; 1 1457; 0 463; 1 497; 0 1423; 1 1457; ---/..--.. --.---/..--.. о 463; 1 1457; 0 463; 1 1457; ө 3343; 1 497; ө 463; 1 497; 0 463; 1 1457; 0 1423; 1 1457; 0 463; 1 497; 0 463; 1 497; e 379 ]; time_unit = 240; disp( tokens_to_str_code( tokens, time_unit ))Create a transparent task of how many 1s each appear on a particular number. Lone means that a number does not appear twice or more in a row. Examples count LoneOnes (101) -2 count LoneOnes (1191) → 1 count LoneOnes (1111) count LoneOnes (462) Solve in Java ScriptSEE MORE QUESTIONS