The Schrodinger equation for an m-mass and q-charged particle, interacting with an electromagnetic field, is expressed as follows (−ih▼ — qA(r, t))² + gó(r,t)] v(r,t). (1) 2m According to the tera transformation, the electromagnetic potential and state of that particle at Eq. (1) changed as follows: A(r, t)→ A'(r, t) = A(r, t) - Vg(r, t) ih (r, t) = (2) (3) (r, t) → (r, t) = e-iqg(r.)/(r,t). (4) By working starting from Eq. (1), Show that transformation in Eqs. (2)-(4) gives the Schrodinge A'(r, t), o'(r. t), and (r. t),, whose shape is the same with Eq. (1). ə o(r, t) → o' (r, t) = o(r, t) + (r, t) equation in In other words, the Schrodinger equation is invariant tera.
The Schrodinger equation for an m-mass and q-charged particle, interacting with an electromagnetic field, is expressed as follows (−ih▼ — qA(r, t))² + gó(r,t)] v(r,t). (1) 2m According to the tera transformation, the electromagnetic potential and state of that particle at Eq. (1) changed as follows: A(r, t)→ A'(r, t) = A(r, t) - Vg(r, t) ih (r, t) = (2) (3) (r, t) → (r, t) = e-iqg(r.)/(r,t). (4) By working starting from Eq. (1), Show that transformation in Eqs. (2)-(4) gives the Schrodinge A'(r, t), o'(r. t), and (r. t),, whose shape is the same with Eq. (1). ə o(r, t) → o' (r, t) = o(r, t) + (r, t) equation in In other words, the Schrodinger equation is invariant tera.
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![The Schrodinger equation for an m-mass and q-charged particle,
interacting with an electromagnetic field, is expressed as follows
ih(r, t)
—ih▼ — qA(r,t))² + qó(r,t)] v(r,t).
(1)
According to the tera transformation, the electromagnetic potential and state of that particle at
Eq. (1) changed as follows:
A(r, t) → A'(r, t) = A(r, t) - Vg(r, t)
Ә
o(r, t) → o'(r, t) = o(r, t) +
at
g(r, t)
(2)
(3)
(r, t) →
(r, t) = e-igg(r.)/(r, t).
By working starting from Eq. (1), Show that transformation in Eqs. (2)-(4) gives the Schrodinger
A'(r, t), o'(r, t), and (r, t),, whose shape is the same with Eq. (1).
equation in
In other words, the Schrodinger equation is invariant tera.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad8301e1-f73c-4e34-b0e5-acd0a1704cde%2F91680ea4-0452-4316-9fc8-1b54c42e4e71%2Foulqoli_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The Schrodinger equation for an m-mass and q-charged particle,
interacting with an electromagnetic field, is expressed as follows
ih(r, t)
—ih▼ — qA(r,t))² + qó(r,t)] v(r,t).
(1)
According to the tera transformation, the electromagnetic potential and state of that particle at
Eq. (1) changed as follows:
A(r, t) → A'(r, t) = A(r, t) - Vg(r, t)
Ә
o(r, t) → o'(r, t) = o(r, t) +
at
g(r, t)
(2)
(3)
(r, t) →
(r, t) = e-igg(r.)/(r, t).
By working starting from Eq. (1), Show that transformation in Eqs. (2)-(4) gives the Schrodinger
A'(r, t), o'(r, t), and (r, t),, whose shape is the same with Eq. (1).
equation in
In other words, the Schrodinger equation is invariant tera.
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