A pion traveling at speed v decays into a muon and a neutrino, л - µ¯ + √₂. If the neutrino emerges at 90° to the original pion direction, at what angle does the è come off? [Answer: tane= (1 − m²/m²)/(2By²).]

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**Physics Problem 3.15**

A pion traveling at speed \( \nu \) decays into a muon and a neutrino: 

\[ \pi^- \rightarrow \mu^- + \overline{\nu}_\mu \].

If the neutrino emerges at \(90^\circ\) to the original pion direction, at what angle does the \( \mu \) come off?

**Answer:** 

\[
\tan \theta = \frac{(1 - m_\mu^2/m_\pi^2)}{(2 \beta \nu^2)}
\]
Transcribed Image Text:**Physics Problem 3.15** A pion traveling at speed \( \nu \) decays into a muon and a neutrino: \[ \pi^- \rightarrow \mu^- + \overline{\nu}_\mu \]. If the neutrino emerges at \(90^\circ\) to the original pion direction, at what angle does the \( \mu \) come off? **Answer:** \[ \tan \theta = \frac{(1 - m_\mu^2/m_\pi^2)}{(2 \beta \nu^2)} \]
Expert Solution
Step 1 To determine,

At what angle does the μ come off.

Given,

π-μ-+ν¯speed of pion=v

 

 

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