The same scenario is used for the remainder of the questions. A psychiatrist clinic classifies its accounts receivable into the following four states State 1. Paid State 2. Bad debt State 3.0-30 days State 4. 31-90 days The clinic currently has $8000 accounts receivable in the 0-30 days state and $2000 in the 31-90 days state. Based on historical transition from week to week of accounts receivable, the following matrix of transition probabilities has been developed for the clinic P= The matrix / - Q can be calculated as O 1.0 0.0 0.0 1.0 1.0 0.0 0.0 1.0 O O 1.0 0.0 0.0 0.0 0.0 1.0 0.0 0.0 0.5 0.0 0.4 0.1 0.6 0.1 0.2 0.1 O 1-Q= 1-Q = 1-Q= I-Q= 1.0 0.0 0.0 1.0 1.0 0.0 0.0 1.0 None of the above 0.4 0.2 0.1 0.1 0.0 0.4 0.1 0.1 0.5 0.0 0.6 0.1 0.4 0.1 = 0]-[20][- 0.2 0.1 0.6 -0.2 -0.1 0.9 1.0 -0.4 -0.1 0.8 0.5 0.0 -0.6 0.9 0.6 -0.1 -0.2 0.9
The same scenario is used for the remainder of the questions. A psychiatrist clinic classifies its accounts receivable into the following four states State 1. Paid State 2. Bad debt State 3.0-30 days State 4. 31-90 days The clinic currently has $8000 accounts receivable in the 0-30 days state and $2000 in the 31-90 days state. Based on historical transition from week to week of accounts receivable, the following matrix of transition probabilities has been developed for the clinic P= The matrix / - Q can be calculated as O 1.0 0.0 0.0 1.0 1.0 0.0 0.0 1.0 O O 1.0 0.0 0.0 0.0 0.0 1.0 0.0 0.0 0.5 0.0 0.4 0.1 0.6 0.1 0.2 0.1 O 1-Q= 1-Q = 1-Q= I-Q= 1.0 0.0 0.0 1.0 1.0 0.0 0.0 1.0 None of the above 0.4 0.2 0.1 0.1 0.0 0.4 0.1 0.1 0.5 0.0 0.6 0.1 0.4 0.1 = 0]-[20][- 0.2 0.1 0.6 -0.2 -0.1 0.9 1.0 -0.4 -0.1 0.8 0.5 0.0 -0.6 0.9 0.6 -0.1 -0.2 0.9
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![The same scenario is used for the remainder of the questions.
A psychiatrist clinic classifies its accounts receivable into the following four states
State 1. Paid
State 2. Bad debt
State 3. 0-30 days
State 4. 31-90 days
The clinic currently has $8000 accounts receivable in the 0-30 days state and $2000 in the 31-90 days state. Based on historical transition from week to week of accounts receivable, the following matrix of transition probabilities has
been developed for the clinic
P =
The matrix / - Q can be calculated as
O
O
O
1.0 0.0 0.0 0.0
0.0 1.0 0.0 0.0
0.5 0.0 0.4 0.1
0.6 0.1 0.2 0.1
O
1 - Q =
1 - Q =
1 - Q =
1 - Q =
1.0 0.0
0.0 1.0
1.0 0.0
0.0 1.0
1.0 0.0
0.0 1.0
1.0 0.0
0.0 1.0
O None of the above
0.4 0.2
0.1 0.1
0.0 0.4
0.1 0.1
0.5 0.0
0.6 0.1
H
=
0.6 -0.2
-0.1 0.9
1.0 -0.4
-0.1 0.8
0.5 0.0
-0.6 0.9
0.4 0.1
1-[20][
0.2 0.1
0.6 0.1
-0.2 0.9](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f27134f-79b5-411d-b0dc-31499a12cd6e%2F7ca16327-a2ec-4f6d-a31a-9cd4d6eb79e3%2F70jd3u7_processed.png&w=3840&q=75)
Transcribed Image Text:The same scenario is used for the remainder of the questions.
A psychiatrist clinic classifies its accounts receivable into the following four states
State 1. Paid
State 2. Bad debt
State 3. 0-30 days
State 4. 31-90 days
The clinic currently has $8000 accounts receivable in the 0-30 days state and $2000 in the 31-90 days state. Based on historical transition from week to week of accounts receivable, the following matrix of transition probabilities has
been developed for the clinic
P =
The matrix / - Q can be calculated as
O
O
O
1.0 0.0 0.0 0.0
0.0 1.0 0.0 0.0
0.5 0.0 0.4 0.1
0.6 0.1 0.2 0.1
O
1 - Q =
1 - Q =
1 - Q =
1 - Q =
1.0 0.0
0.0 1.0
1.0 0.0
0.0 1.0
1.0 0.0
0.0 1.0
1.0 0.0
0.0 1.0
O None of the above
0.4 0.2
0.1 0.1
0.0 0.4
0.1 0.1
0.5 0.0
0.6 0.1
H
=
0.6 -0.2
-0.1 0.9
1.0 -0.4
-0.1 0.8
0.5 0.0
-0.6 0.9
0.4 0.1
1-[20][
0.2 0.1
0.6 0.1
-0.2 0.9
![QUESTION 2
Compute the fundamental matrix N = (I- Q) -1
O
O
O
N = (I- Q) -1=
O
N = (I- Q) -1=
_N = (I- Q) -1=
N = (1− Q) -1=
O None of the above
1
0.9 0.2
(0.6) (0.9)-(-0.2) (-0.1) 0.1 0.6
1
0.9 0.1
(0.6) (0.9) (-0.2) (-0.1) 0.2 0.6
0.8 0.4
(1.0) (0.8) (-0.1) (-0.4) 0.1 1.0
1
=
(0.5) (0.9)-(-0.6) (0.0) 0.6 0.5
=
=
1 0.9 0.2
0.1 0.6
0.52
1
0.52
0.9 0.1
0.2 0.6
1
0.8 0.4
0.76 0.1 1.0
1
1
-0.6) (0.0) (0.5 0.3-0.45 (0.8 0.8]-
=
38 318 3 35 38
90
90 20
52 52
10 60
52 50
10
52
20 60
50
40 20
38
45
50
38
0 4
60 50
45 45
1.7308 0.3846
0.1923 1.1538
1.7308 0.1923
0.3846 1.1538
1.0526 0.5263
0.1316 1.3158
2.0000 0.0000
1.3333 1.1111](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f27134f-79b5-411d-b0dc-31499a12cd6e%2F7ca16327-a2ec-4f6d-a31a-9cd4d6eb79e3%2F946cbtl_processed.png&w=3840&q=75)
Transcribed Image Text:QUESTION 2
Compute the fundamental matrix N = (I- Q) -1
O
O
O
N = (I- Q) -1=
O
N = (I- Q) -1=
_N = (I- Q) -1=
N = (1− Q) -1=
O None of the above
1
0.9 0.2
(0.6) (0.9)-(-0.2) (-0.1) 0.1 0.6
1
0.9 0.1
(0.6) (0.9) (-0.2) (-0.1) 0.2 0.6
0.8 0.4
(1.0) (0.8) (-0.1) (-0.4) 0.1 1.0
1
=
(0.5) (0.9)-(-0.6) (0.0) 0.6 0.5
=
=
1 0.9 0.2
0.1 0.6
0.52
1
0.52
0.9 0.1
0.2 0.6
1
0.8 0.4
0.76 0.1 1.0
1
1
-0.6) (0.0) (0.5 0.3-0.45 (0.8 0.8]-
=
38 318 3 35 38
90
90 20
52 52
10 60
52 50
10
52
20 60
50
40 20
38
45
50
38
0 4
60 50
45 45
1.7308 0.3846
0.1923 1.1538
1.7308 0.1923
0.3846 1.1538
1.0526 0.5263
0.1316 1.3158
2.0000 0.0000
1.3333 1.1111
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