The route followed by a hiker consists of three displacement vectors A, B, and C. Vector A is along a measured trail and is 1550 m in a direction 25.0° north of east. Vector B is not along a measured trail, but the hiker uses a compass and knows that the direction is 41.0° east of south. Similarly, the direction of Cis 35.0° north of west. The hiker ends up where she started. Therefore, it follows that the resultant displacement is zero, or A + B + C = 0. What is the magnitude of vector ? O 4790 m O 6140 m O 7230 m O 5550 m O 3530 m Submit Answer Save for Later

College Physics
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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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Wondering if you can help me spot where I went wrong. Working with vectors with distance and no magnitude

8
#19
X =
250 N fe
E
A = 1550m 250 N
B² = B 41° east of south
C² €35° North of Wast
410
c>
Ay-
330
Ax = 1550m Ay = Sin (25°) (1550m): 655.1m
Bx = Sin (419) B = .656 B
By = Cos (41⁰) B = .755B
Cx = Cos (35°)C=819c
C₁ = Sin (35°) c = .574 c
2
1550 m +.656 BT-819c=0/1/
655.1m-.755B +. 574C = 0
y²
655.1m- 755B +.574C =0 -D 655.1m +.574C = ⋅755B
FO
+755B
1155
755
B = 867.7m +.760c
PLUG IN
re
1550m +.656(867.7m +.760c) - 819 c =0
1550m + 569.211 m +.499 € - .819c2119.21-300=0
2119.21-32c-0 -0 2119.21=32c
•32 c=6622,5m
CA
IQ5°
w+c
S
A²7
OF
1-1
Transcribed Image Text:8 #19 X = 250 N fe E A = 1550m 250 N B² = B 41° east of south C² €35° North of Wast 410 c> Ay- 330 Ax = 1550m Ay = Sin (25°) (1550m): 655.1m Bx = Sin (419) B = .656 B By = Cos (41⁰) B = .755B Cx = Cos (35°)C=819c C₁ = Sin (35°) c = .574 c 2 1550 m +.656 BT-819c=0/1/ 655.1m-.755B +. 574C = 0 y² 655.1m- 755B +.574C =0 -D 655.1m +.574C = ⋅755B FO +755B 1155 755 B = 867.7m +.760c PLUG IN re 1550m +.656(867.7m +.760c) - 819 c =0 1550m + 569.211 m +.499 € - .819c2119.21-300=0 2119.21-32c-0 -0 2119.21=32c •32 c=6622,5m CA IQ5° w+c S A²7 OF 1-1
V D2L S D2L F
WP NNX
FTC (24
GTGV
+
→ C
ops G YouTube
education.wiley.com/was/ui/v2/adaptive-assessment-player/index.html?launchId=9ccf40ba-cfac-40a1-b5e6-6d27dfdcb45d#/activity
Bartender M Gmail YouTube N WeBWork: S_RR... WeBWork: S_RR...
Other Bookmarks EE
Chapter 1 Adaptive Practice
1.8 Addition of Vectors by Means of Components
The route followed by a hiker consists of three displacement vectors A, B, and C. Vector A is along a measured trail and is 1550 m
in a direction 25.0° north of east. Vector B is not along a measured trail, but the hiker uses a compass and knows that the direction is
41.0° east of south. Similarly, the direction of is 35.0° north of west. The hiker ends up where she started. Therefore, it follows
that the resultant displacement is zero, or A + B + C = 0. What is the magnitude of vector C ?
O 4790 m
0 6140 m
O 7230 m
0 5550 m
O 3530 m
Save for Later
Submit Answer
W
PHY111 Materia....docx
eScience Lab Sa....pdf
ime....docx
nglish (United States)
W PHY1111 Lab 1....docx
F
Focus
Transcribed Image Text:V D2L S D2L F WP NNX FTC (24 GTGV + → C ops G YouTube education.wiley.com/was/ui/v2/adaptive-assessment-player/index.html?launchId=9ccf40ba-cfac-40a1-b5e6-6d27dfdcb45d#/activity Bartender M Gmail YouTube N WeBWork: S_RR... WeBWork: S_RR... Other Bookmarks EE Chapter 1 Adaptive Practice 1.8 Addition of Vectors by Means of Components The route followed by a hiker consists of three displacement vectors A, B, and C. Vector A is along a measured trail and is 1550 m in a direction 25.0° north of east. Vector B is not along a measured trail, but the hiker uses a compass and knows that the direction is 41.0° east of south. Similarly, the direction of is 35.0° north of west. The hiker ends up where she started. Therefore, it follows that the resultant displacement is zero, or A + B + C = 0. What is the magnitude of vector C ? O 4790 m 0 6140 m O 7230 m 0 5550 m O 3530 m Save for Later Submit Answer W PHY111 Materia....docx eScience Lab Sa....pdf ime....docx nglish (United States) W PHY1111 Lab 1....docx F Focus
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