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The route followed by a hiker consists of three displacement vectors A, B, and C. Vector A is along a measured trail and is 1550 m in a direction 25.0° north of east. Vector B is not along a measured trail, but the hiker uses a compass and knows that the direction is 41.0° east of south. Similarly, the direction of Cis 35.0° north of west. The hiker ends up where she started. Therefore, it follows that the resultant displacement is zero, or A + B + C = 0. What is the magnitude of vector ? O 4790 m O 6140 m O 7230 m O 5550 m O 3530 m Submit Answer Save for Later

The route followed by a hiker consists of three displacement vectors A, B, and C. Vector A is along a measured trail and is 1550 m in a direction 25.0° north of east. Vector B is not along a measured trail, but the hiker uses a compass and knows that the direction is 41.0° east of south. Similarly, the direction of Cis 35.0° north of west. The hiker ends up where she started. Therefore, it follows that the resultant displacement is zero, or A + B + C = 0. What is the magnitude of vector ? O 4790 m O 6140 m O 7230 m O 5550 m O 3530 m Submit Answer Save for Later

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Wondering if you can help me spot where I went wrong. Working with vectors with distance and no magnitude

8 #19 X = 250 N fe E A = 1550m 250 N B² = B 41° east of south C² €35° North of Wast 410 c> Ay- 330 Ax = 1550m Ay = Sin (25°) (1550m): 655.1m Bx = Sin (419) B = .656 B By = Cos (41⁰) B = .755B Cx = Cos (35°)C=819c C₁ = Sin (35°) c = .574 c 2 1550 m +.656 BT-819c=0/1/ 655.1m-.755B +. 574C = 0 y² 655.1m- 755B +.574C =0 -D 655.1m +.574C = ⋅755B FO +755B 1155 755 B = 867.7m +.760c PLUG IN re 1550m +.656(867.7m +.760c) - 819 c =0 1550m + 569.211 m +.499 € - .819c2119.21-300=0 2119.21-32c-0 -0 2119.21=32c •32 c=6622,5m CA IQ5° w+c S A²7 OF 1-1
Transcribed Image Text:8 #19 X = 250 N fe E A = 1550m 250 N B² = B 41° east of south C² €35° North of Wast 410 c> Ay- 330 Ax = 1550m Ay = Sin (25°) (1550m): 655.1m Bx = Sin (419) B = .656 B By = Cos (41⁰) B = .755B Cx = Cos (35°)C=819c C₁ = Sin (35°) c = .574 c 2 1550 m +.656 BT-819c=0/1/ 655.1m-.755B +. 574C = 0 y² 655.1m- 755B +.574C =0 -D 655.1m +.574C = ⋅755B FO +755B 1155 755 B = 867.7m +.760c PLUG IN re 1550m +.656(867.7m +.760c) - 819 c =0 1550m + 569.211 m +.499 € - .819c2119.21-300=0 2119.21-32c-0 -0 2119.21=32c •32 c=6622,5m CA IQ5° w+c S A²7 OF 1-1
V D2L S D2L F WP NNX FTC (24 GTGV + → C ops G YouTube education.wiley.com/was/ui/v2/adaptive-assessment-player/index.html?launchId=9ccf40ba-cfac-40a1-b5e6-6d27dfdcb45d#/activity Bartender M Gmail YouTube N WeBWork: S_RR... WeBWork: S_RR... Other Bookmarks EE Chapter 1 Adaptive Practice 1.8 Addition of Vectors by Means of Components The route followed by a hiker consists of three displacement vectors A, B, and C. Vector A is along a measured trail and is 1550 m in a direction 25.0° north of east. Vector B is not along a measured trail, but the hiker uses a compass and knows that the direction is 41.0° east of south. Similarly, the direction of is 35.0° north of west. The hiker ends up where she started. Therefore, it follows that the resultant displacement is zero, or A + B + C = 0. What is the magnitude of vector C ? O 4790 m 0 6140 m O 7230 m 0 5550 m O 3530 m Save for Later Submit Answer W PHY111 Materia....docx eScience Lab Sa....pdf ime....docx nglish (United States) W PHY1111 Lab 1....docx F Focus
Transcribed Image Text:V D2L S D2L F WP NNX FTC (24 GTGV + → C ops G YouTube education.wiley.com/was/ui/v2/adaptive-assessment-player/index.html?launchId=9ccf40ba-cfac-40a1-b5e6-6d27dfdcb45d#/activity Bartender M Gmail YouTube N WeBWork: S_RR... WeBWork: S_RR... Other Bookmarks EE Chapter 1 Adaptive Practice 1.8 Addition of Vectors by Means of Components The route followed by a hiker consists of three displacement vectors A, B, and C. Vector A is along a measured trail and is 1550 m in a direction 25.0° north of east. Vector B is not along a measured trail, but the hiker uses a compass and knows that the direction is 41.0° east of south. Similarly, the direction of is 35.0° north of west. The hiker ends up where she started. Therefore, it follows that the resultant displacement is zero, or A + B + C = 0. What is the magnitude of vector C ? O 4790 m 0 6140 m O 7230 m 0 5550 m O 3530 m Save for Later Submit Answer W PHY111 Materia....docx eScience Lab Sa....pdf ime....docx nglish (United States) W PHY1111 Lab 1....docx F Focus
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