Given the vectors M = –10ā, + 4ãy – 8ā, and N = 8ãx +7ãy – 2āz, find: %3D a. A unit vector in the direction of –M + 2Ñ b. The magnitude of 5å, + N – 3M c. M||2Ñ|(M + Ñ)
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- MY NOTE ASK YOUR TEACHER Displacement vector A points due east and has a magnitude of 1.9 km. Displacement vector B points due north and has a magnitude of 2.44 km. Displacement vector points due south and has a magnitude of 1.8 km. Find the magnitude and direction (relative to due east) of the resultant points due west and has a magnitude of 2.6 km. Displacement vector D vector A + B +C+D. magnitude km o e direction o counterclockwise from due east Additional Materials teps... eBook I were pre option em... 8? ? TOO 1,631 OCT 8. MacBook Air esc DOO DDO FA F1 74 F2 F3 F5 %24 2 3 6The position of a particle, A, with respect to a particle, B, can be expressed as ra/B = rA- rB Where the subscript notation A/B means: O The vector from the origin to particle A. O Bwith respect to A. O The vector from the origin to particle B. O A with respect to B.pls help ASAP, not sure what I did wrong, thanks!
- I 2 BE Suppose you walk 13.0 m straight west and then 21.0 m straight north. How far are you from your starting point, 25 m what is angle of the resultant vector, 57.5 O and what is the compass direction of a line connecting your starting point to your final position? 58 X °W of NF3 65° 35° F, The magnitude of the vector is F2=1.5N .What is the rectangular component of vector F2 ? * The magnitude of the vector is F2 = 1.5N. What is the rec tan gular component of vector F2? O (1.5N cos 65°) i + (1.5N cos 35°) j O (1.5N cos 35°) i + (1.5N cos 55°) j O (1.5 N) i + ( 1.5N ) j O (1.5N cos 55°) i + (1.5N cos 35°) jQ(2) Consider the two vectors A= 31 – 2j and B = 2i – 3j. Calculate the angle between the two vectors A) 146° B) 47.7° C) 70° D) 22.6° O 1. D O 2. B O 3. C O 4. A
- 1.8 Addition of Vectors by Means of Components A = 10.0 at 30 ° above the +x-axis; B - 12.0 at 60° above the +x-axis; and C - = 15.0 at 50 ° below the -x-axis. What is the magnitude of Å + B+ C? O 6.1 O 25 O 8.6 O 37 O 6.4 Save for Later Submit Answer pouse break prt sc sysra delete bome backspoceComplete the table below: Vector 1 Vector 2 Vector 3 Vector 4 Vector 5 Vector 6 x-component 15m 2cm 5N 3lbf 2cm 3mm y-component Magnitude 100N 25m 5lbf Direction 30° W of N 40° s of E NE Solve what is asked: 1. What is the resultant of Vectors 1, 3 and 5? 2. What is the Vector 4 – Vector 2 + Vector 6? 3. If Vector 7 is 3i + 4j, then what is Vector 3 + Vector 7? 4. If Vector 7 is 3i + 4j, then what is Vector 6 - Vector 7?Please help mw
- 0 аф sin þa, + tan— Înr aº at P(2‚ñ/2,3/2). Determine If A = r sin 0 cosa, - cos 20 sin þaŋ + tan cos 20 the vector component of A that is parallel to az (express your answer in spherical coordinates)Two vectors %3D 2 and B = 2 + 3 . Find the approximate angle between the vectors (-3 A ) and (2 )? .A None .B 30° .C 60°46. ECHALK The three displacement vectors in the drawing have mag- nitudes of A = 5.00 m, B = 5.00 m, and C= 4.00 m. Find the resultant (magnitude and directional angle) of the three vectors by means of the com- ponent method. Express the directional angle as an angle above the positive or negative x axis. PROBLEM 46 Ä 20.0° C B 60.0⁰ +1