Vector A= 1.008 -2.00P, vector B =3.008 + 4.009. what is the direction of vector 56.3 counterclockwise from the positive x axis 26.6° counterclockwise from the positive x axis O 30.0° counterclockwise from the positive x axis 60.0° counterclockwise from the positive x axis O 33.7° counterclockwise from the positive x axis
Vector A= 1.008 -2.00P, vector B =3.008 + 4.009. what is the direction of vector 56.3 counterclockwise from the positive x axis 26.6° counterclockwise from the positive x axis O 30.0° counterclockwise from the positive x axis 60.0° counterclockwise from the positive x axis O 33.7° counterclockwise from the positive x axis
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter3: Vectors
Section: Chapter Questions
Problem 65PQ
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Question
![### Vector Addition and Direction Calculation
In this problem, we are given two vectors and need to determine the direction of their sum.
#### Given Vectors:
- Vector \( \mathbf{A} = 1.00\hat{i} - 2.00\hat{j} \)
- Vector \( \mathbf{B} = 3.00\hat{i} + 4.00\hat{j} \)
#### Task:
What is the direction of vector \( \mathbf{C} = \mathbf{A} + \mathbf{B} \)?
#### Options:
- \( \circ \) 56.3° counterclockwise from the positive x-axis
- \( \circ \) 26.6° counterclockwise from the positive x-axis
- \( \circ \) 30.0° counterclockwise from the positive x-axis
- \( \circ \) 60.0° counterclockwise from the positive x-axis
- \( \circ \) 33.7° counterclockwise from the positive x-axis
### Calculating the Sum of Vectors:
To find vector \( \mathbf{C} \), we add corresponding components of vectors \( \mathbf{A} \) and \( \mathbf{B} \).
\[ \mathbf{C} = \mathbf{A} + \mathbf{B} \]
\[ \mathbf{C} = (1.00\hat{i} - 2.00\hat{j}) + (3.00\hat{i} + 4.00\hat{j}) \]
\[ \mathbf{C} = (1.00 + 3.00)\hat{i} + (-2.00 + 4.00)\hat{j} \]
\[ \mathbf{C} = 4.00\hat{i} + 2.00\hat{j} \]
Now, we must find the direction of vector \( \mathbf{C} \). The direction θ is given by:
\[ \theta = \tan^{-1} \left( \frac{C_y}{C_x} \right) \]
Where \( C_y \) and \( C_x \) are the y and x components of vector \( \mathbf{C} \), respectively.
\[ \theta = \tan^{-1} \left( \frac{2.00}{4.00} \right)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd955a64d-1d84-4c4c-a975-e65e2fa2eacb%2F445e1776-ff52-43c0-8717-dd4a5bf5d948%2F6cacyji_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Vector Addition and Direction Calculation
In this problem, we are given two vectors and need to determine the direction of their sum.
#### Given Vectors:
- Vector \( \mathbf{A} = 1.00\hat{i} - 2.00\hat{j} \)
- Vector \( \mathbf{B} = 3.00\hat{i} + 4.00\hat{j} \)
#### Task:
What is the direction of vector \( \mathbf{C} = \mathbf{A} + \mathbf{B} \)?
#### Options:
- \( \circ \) 56.3° counterclockwise from the positive x-axis
- \( \circ \) 26.6° counterclockwise from the positive x-axis
- \( \circ \) 30.0° counterclockwise from the positive x-axis
- \( \circ \) 60.0° counterclockwise from the positive x-axis
- \( \circ \) 33.7° counterclockwise from the positive x-axis
### Calculating the Sum of Vectors:
To find vector \( \mathbf{C} \), we add corresponding components of vectors \( \mathbf{A} \) and \( \mathbf{B} \).
\[ \mathbf{C} = \mathbf{A} + \mathbf{B} \]
\[ \mathbf{C} = (1.00\hat{i} - 2.00\hat{j}) + (3.00\hat{i} + 4.00\hat{j}) \]
\[ \mathbf{C} = (1.00 + 3.00)\hat{i} + (-2.00 + 4.00)\hat{j} \]
\[ \mathbf{C} = 4.00\hat{i} + 2.00\hat{j} \]
Now, we must find the direction of vector \( \mathbf{C} \). The direction θ is given by:
\[ \theta = \tan^{-1} \left( \frac{C_y}{C_x} \right) \]
Where \( C_y \) and \( C_x \) are the y and x components of vector \( \mathbf{C} \), respectively.
\[ \theta = \tan^{-1} \left( \frac{2.00}{4.00} \right)
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