The reversible chemical reaction has the following equilibrium constant: A+B=C+D CD K₂=AB= 4.1 Initially, only A and B are present, each at 2.00 M. What is the final concentration of A once equilibrium is reached? Express your answer to two significant figures and include the appropriate units. ▸ View Available Hint(s) (A) - 0.57 Submit for Part A for Party do for Part redo foart A relor Part A keyboard shortcuts for Part A help for Part A mol L Part B Previous Answers X Incorrect; Try Again; 2 attempts remaining What is the final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] =2.00 M? Express your answer to two significant figures and include the appropriate units.

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Chapter1: Chemical Foundations
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The reversible chemical reaction
has the following equilibrium constant:
A+B=C+D
Kc =
[C][D]
= 4.1
[A][B]
Part A
Initially, only A and B are present, each at 2.00 M. What is the final concentration of A once equilibrium is reached?
Express your answer to two significant figures and include the appropriate units.
► View Available Hint(s)
[A] = 0.57
Submit Previous Answers
for Part A for Part A do for Part redo foart A
Part B
X Incorrect; Try Again; 2 attempts remaining
[D] =
Submit
mol
L
What is the final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M?
Express your answer to two significant figures and include the appropriate units.
► View Available Hint(s)
for Rart B for Part B do for Part
Value
redo for Part A refor Part A keyboard shortcuts for Part A help for Part A
Units
redo for part B restor Part B keyboard shortcuts for Part B help for Part B
Transcribed Image Text:The reversible chemical reaction has the following equilibrium constant: A+B=C+D Kc = [C][D] = 4.1 [A][B] Part A Initially, only A and B are present, each at 2.00 M. What is the final concentration of A once equilibrium is reached? Express your answer to two significant figures and include the appropriate units. ► View Available Hint(s) [A] = 0.57 Submit Previous Answers for Part A for Part A do for Part redo foart A Part B X Incorrect; Try Again; 2 attempts remaining [D] = Submit mol L What is the final concentration of D at equilibrium if the initial concentrations are [A] = 1.00 M and [B] = 2.00 M? Express your answer to two significant figures and include the appropriate units. ► View Available Hint(s) for Rart B for Part B do for Part Value redo for Part A refor Part A keyboard shortcuts for Part A help for Part A Units redo for part B restor Part B keyboard shortcuts for Part B help for Part B
Part B
Based on a Ke value of 0.250 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively?
Express the molar concentrations numerically.
▸ View Available Hint(s)
for Part B for Part B do for Part
th
redo for Part B reset or Part B keyboard shortcuts for Part B help for Part B
[XY], [X], [Y] = 0.372,0.228,0.228
Submit Previous Answers
X Incorrect; Try Again; 4 attempts remaining
Calculating equilibrium concentrations when the net reaction proceeds in reverse
Consider mixture C, which will cause the net reaction to proceed in reverse.
Part C
The change in concentration, x, is positive for the reactants because they are produced and negative for the products because they are consumed.
Based on a Ke value of 0.250 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively?
Express the molar concentrations numerically.
► View Available Hint(s)
for Part C
for Part C
for Part C
vec
[XY], [X], [Y] = 0.372,0.228,0.228
do for Part
Submit Previous Answers
X Incorrect; Try Again; 5 attempts remaining
M
redo for Part C reset for Part C keyboard shortcuts for Part C help for Part C
M
Concentration (M) [XY]
0.200
+x
0.200 + x
initial:
change:
equilibrium:
← net
1L
[X]
0.300
-x
0.300 - x
+ [Y]
0.300
-x
0.300 - x
Transcribed Image Text:Part B Based on a Ke value of 0.250 and the given data table, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. ▸ View Available Hint(s) for Part B for Part B do for Part th redo for Part B reset or Part B keyboard shortcuts for Part B help for Part B [XY], [X], [Y] = 0.372,0.228,0.228 Submit Previous Answers X Incorrect; Try Again; 4 attempts remaining Calculating equilibrium concentrations when the net reaction proceeds in reverse Consider mixture C, which will cause the net reaction to proceed in reverse. Part C The change in concentration, x, is positive for the reactants because they are produced and negative for the products because they are consumed. Based on a Ke value of 0.250 and the data table given, what are the equilibrium concentrations of XY, X, and Y, respectively? Express the molar concentrations numerically. ► View Available Hint(s) for Part C for Part C for Part C vec [XY], [X], [Y] = 0.372,0.228,0.228 do for Part Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining M redo for Part C reset for Part C keyboard shortcuts for Part C help for Part C M Concentration (M) [XY] 0.200 +x 0.200 + x initial: change: equilibrium: ← net 1L [X] 0.300 -x 0.300 - x + [Y] 0.300 -x 0.300 - x
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