The results of a standard Proctor test are given in the following table. Given: Mold volume = 1/30 ft^3 and Gs = 2.69. Determine the void ratio and the degree of saturation at the optimum moisture content. Trial # Weight of moist soil in the mold (lb) Moisture content (%) 1 3.7 8.6 2 4.15 10.6 3 4.69 12.5 4 4.62 14.9 5 4.02 16.7 6 3.63 18.3

Q: x=5

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Q: Engineering statistics, i need solutions in 15 minutes please. MCQ/The table below shows the results…

A: Specific gravity Number of sample cumulative frequency 2.30-2.39 1 1 2.40-2.49 2 1+2=3…

Q: 0.1.A A soil specimen have void ratio (e) of 0.7, Gs 2.72. Calculate the total unit weight, dry unit…

A: A) Given that soil specimen is having  Void ratio (e) = 0.7 Specific Gravity (Gs) = 2.72 Degree of…

Q: Following the sieve analysis and the specific gravity of "SAND 1", a hydrometer test was performed…

A: The hydrometer test is used to determine the distribution of soil particle sizes that are smaller…

Q: (b) From your curve, obtain the values of: (i) D10 ; D30 ; D0 (ii) Coefficient of uniformity, C.…

A: from the particle size disrtibution curve, you will get the values of D10, D30 and D60.henceusing…

Q: The moist unit weight of 0.0057 m³ of a soil is 102.6 N. The moisture content and the specific…

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Q: The detailed results of a standard Proctor test on a soil classified as CL-ML and group name silty…

A: Given: Volume of Mould=130ft3                               = 934.46 cm3 Weight of mould= 4.45 lb…

Q: Sieve and Atterberg limits tests were made on a soil specimen and results are given below: Sieve No.…

A: Solution- The calculation is shown is shown in the table, Sieve No. Weight of soil, g Weight…

Q: 6.41 The results of a standard Proctor test are given in the following table. a. Determine the…

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Q: LL=25% PI=15% Cu=_____

A: From graph :D60=0.05mmD30=0.0026mmD10=0.0007mmFind uniformity coeff:Cu=D60D10=0.050.0007=71.4285Find…

Q: A laboratory test was conducted according to Method A of the ASTM D4318 to find the liquid limit of…

A: The wet mass of the soil sample with the mass of the can is measured, again the dry mass of the…

Q: Problem 1: The table below present the results of a standard proctor test of a borrow pit soil. FEB…

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Q: LL=25% PI=15%   a. D10, D30, and D60 b. Uniformity coefficient, Cu

A: Sieve   Mass  % Cumulative % Cumulative % No Sieve size Retained mass Retained Retained Passing…

Q: Problem 1: The table below present the results of a standard proctor test of a borrow pit soil. Mass…

A: NOTE : AS per company guidelines, we are obliged to answer only one question at a time. Please ask…

Q: 2.7 The results of a liquid limit test and a plastic limit test on a sample of soil are given below:…

A: To find - Liquid limit, plastic limit, Plasticity index and classification of soil based on the…

Q: How do i solve problem 6.4 a & b

A: The given data is shown below:

Q: TABLE 2 RESULTS OF ORI TEST Water Content (%) Weight (Kg) 14 1.45 16.5 1.71 18.5 1.87 20 1.88 21…

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Q: Paragraph Liquid Limit Determination Specimen No. No. of Blows Wt. of Container Wt. of Container +…

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Q: Q3- A sieve analysis on soil sample showed the following results; Size, mm T2 4.75 2.00 0.84 0.42…

A: Solution Given Data Size, mm 12 4.75 2.00 0.84 0.42 0.25 0.15 0.075 0.001 % finer 100 63 57 49…

Q: 6. The results of a standard Proctor Test are tabulated as follows. Volume of Proctor Mold(ft³)…

A: a) Calculate the bulk density ,moist unit weight and dry density as given as , Bulk density =weight…

Q: i) Plot the grain size distribution curve on the log graph that has been provided (Figure 2b).…

A: Given data,

Q: Problem-1 A soil sample, taken from a borrow pit has a specific gravity of soil solids of 2.65. The…

A: Optimum moisture content, OMC is the water/moisture content at which the soil attains maximum dry…

Q: Sieve Size Sieve opening (mm) Percent Finer 3 in. 76.2 100% 2 in. 50.8 90% 1 in. 25.4 80% #4 4.75…

A: Given the sieve sizes and percentage finer soil in those sieves.

Q: The laboratory test data for a standard Proctor test are given below. Volume of Moisture content…

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Q: A Sample of soil was tested in the laboratory, and the test results were listed as follows. Classify…

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Q: 943.3 1.70 943.3 1.85 943.3 1.90 943.3 1.99 943.3 2.05 943.3 1.96 943.3 1.92

A: Standard proctor test Moist unit weight = wet soil / volume  Dry unit weight = moist unit weight /…

Q: A compaction test was conducted in a soils laboratory using the Standard Proctor Method B test…

A: In a standard proctor test of a sample The weight of the compact soil specimen plus mold and the…

Q: A cohesive soil sample is subjected to an unconfined compression test.  The sample fails at a…

A: Given:- A cohesive soil sample is subjected to an unconfined compression test The sample fails at a…

Q: A series of identical samples have been tested with drained triaxial test and some of the values are…

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Q: • Problem 3- From the following data of the grain size analysis Sieve size #4 #8 # 10 #25 #60 # 100…

A: To Determine :- a) Cu & Cc b) classify the soil using USCS soil classification system.

Q: Natural Water Content Soil Wt. of Wet Soil Wt. of Dry Soil Sample (kg) (kg) 1 9.69 7.0 2 9.47 6.86

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Q: Two soil specimens with identical geometric dimensions were subjected to falling head permeability…

A: Given,  The ratio of initial and final water heads for the first specimen, =  h1/h2= 1.25 And, K2=…

Q: Sieve analysis was performed on a 1.565 lb dry soil sample "SAND 1", and the following data was…

A: sieve(in)diameter(mm)mass of sieve(lb) m1mass of sieve+retained soil(lb) m2mass retained(m2-m1)%…

Q: II. Data and Results (use dummy data) Given are data and results of the sand cone method experiment.…

A: Weight of sand = (m1-m2)×9.81 ( To get the weight of sand subtract the mold weight from the weight…

Q: 2a. The following data was obtained from Liquid Limit Test conducted at a Soil Lab. Using the data…

A: Given data:- Specimen number 2 3 No of blows 20 28 W1 (G) 7.31 7.78 W2 (G) 27.31 28.41 W3…

Q: Sieve and Atterberg limits tests Wt. of sieve (gm) Wt. of sieve + Soil (gm) 450 518 378 420 L.L =…

A: The given data is shown below:

Q: Situation 5: Following is the result of a standard procfor test. UnitWeight Trial 7 Proctor mold…

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Soil Compaction Test

Soil compaction is the major area of geotechnical engineering. Soil is composed of multiple pores present on its surface, while the soil is mainly composed of gravel, sand, rocks, etc. The arrangement of these rocks and gravels is such that they build up voids (spaces) between them, which allows spaces for the roots of the plants and crops to spread and absorb the required amount of nutrients. Soil compaction is a major problem primarily caused by human activities, micro-organisms, and other multiple factors.