The resultant solution had a freezing point of 177.9 °C when 0.270 g of the solute was dissolved in 50.0 g of C10H160. (Kt = 37.7 °C.kg/mol for pure C10H160 at 179.8 %3D °C.) The quantity of CO2 generated when 0.270 g of the substance was burnt in excess of O2 reacted fully with 20.0 mL of 2.00 M KOH solution according to the equation. 20H-(aq) + CO2(g) → CO3-2(aq) + H2O(1) What is the molecular formula of the compound? C6H6 C6H12

The resultant solution had a freezing point of 177.9 °C when 0.270 g of the solute was dissolved in 50.0 g of C10H160. (Kt = 37.7 °C.kg/mol for pure C10H160 at 179.8 %3D °C.) The quantity of CO2 generated when 0.270 g of the substance was burnt in excess of O2 reacted fully with 20.0 mL of 2.00 M KOH solution according to the equation. 20H-(aq) + CO2(g) → CO3-2(aq) + H2O(1) What is the molecular formula of the compound? C6H6 C6H12

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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