The result of specific gravity test is given below Weightof saturated aggregate in water =618gmWeight of oven dry sample = 982 gmWeight of saturated surface dry aggregate = 990 gmO Caleulate the specific gravity of aggregate?(ii) calculate the apparent specific gravity of aggregate.

Given, Weight of saturated aggregate in water= 618gm Weight of oven dried sample= 982gm Weight of…

Answered: The result of specific gravity test is…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Coarse aggregate is placed in a rigid bucket and compacted with a tamping rod to determineits unit weight. The following data are obtained:• Volume of bucket = 0.5 ft3• Weight of empty bucket = 20.3 lb• Weight of bucket filled with dry compacted coarse aggregate = 76.8 lba) Calculate the dry-compacted unit weight of the aggregate.b) If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids.
Laboratory specific gravity and absorption tests are run on two coarse aggregate sizes, which have to be blended. The results are as follows: Aggregate A: Buck specific gravity = 2.395; absorption = 4.69% Aggregate B: Buck specific gravity = 2.601; absorption = 0.51% What is the specific gravity of a mixture of 50]% aggregate A and 50% aggregate B by weight?
If needed assume the unit weight of water to be 62.4 lb/ft3 a) A HMAC sample has the following volumetric properties (i) VMA = 0.1865 ft3and (ii)Volume of air = 0.0452 ft3 Compute %VFA. b) A HMAC sample has 140 lbs of aggregate with a bulk specific gravity of 2.65 and aneffective specific gravity of 2.71. Based on this information the volume of the absorbedasphalt is ________________ft3A compacted sample of hot mix asphalt concrete sample has a unit weight of 135 lb/ft3.c) The sample has an asphalt content of 5% (by weight). Assume no absorbed asphalt.The bulk specific gravity of the aggregate is 2.65, and specific gravity for the asphaltcement is 1.05. Based on this information compute VMA for this mixture.

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The result of specific gravity test is given below Weight of saturated aggregate in water =618gm Weight of oven dry sample = 982 gm Weight of saturated surface dry aggregate = 990 gm ) Calculate the specific gravity of aggregate? (ii) calculate the apparent specific gravity of aggregate.