"The residential smoke detector. Residential smoke detectors use a simple ionization chamber, open to the air, and a small radioactive pellet that ionizes the air inside the chamber at a constant rate. The source is americum-241 (Am- 241), which produces mostly heavy a particles (these are easily absorbed in air and can only propagate about 3 cm). Smoke detectors contain approximately 0.3 µg of Am-241. The activity of Am-241 is 3.7 x 10° Bq and the ionization energy of the a particles it emits is 5.486 x 105 ev. Assuming the efficiency is 85%, calculate the ionization current (in nA) that will flow in the chamber if the potential across the chamber is high enough to attract all charges without recombination." 0.924 1.848 0.785 1.220

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"The residential smoke detector. Residential smoke detectors use a simple ionization chamber, open to the air, and a
small radioactive pellet that ionizes the air inside the chamber at a constant rate. The source is americum-241 (Am-
241), which produces mostly heavy a particles (these are easily absorbed in air and can only propagate about 3 cm).
Smoke detectors contain approximately 0.3 µg of Am-241. The activity of Am-241 is 3.7 x 10° Bq and the ionization
energy of the a particles it emits is 5.486 x 10° ev. Assuming the efficiency is 85%, calculate the ionization current (in
nA) that will flow in the chamber if the potential across the chamber is high enough to attract all charges without
recombination."
0.924
1.848
0.785
1.220
None of the above
Transcribed Image Text:"The residential smoke detector. Residential smoke detectors use a simple ionization chamber, open to the air, and a small radioactive pellet that ionizes the air inside the chamber at a constant rate. The source is americum-241 (Am- 241), which produces mostly heavy a particles (these are easily absorbed in air and can only propagate about 3 cm). Smoke detectors contain approximately 0.3 µg of Am-241. The activity of Am-241 is 3.7 x 10° Bq and the ionization energy of the a particles it emits is 5.486 x 10° ev. Assuming the efficiency is 85%, calculate the ionization current (in nA) that will flow in the chamber if the potential across the chamber is high enough to attract all charges without recombination." 0.924 1.848 0.785 1.220 None of the above
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