A solution of In-111 DTPA from the Amersham Corp. in Great Britain arrives in your department with the following calibration data: Activity Volume Date Time 10.0 MBq 0.20 mL Oct. 15 1200 PST Look up the half-life of In-111 in your textbook or the Chart of the Nuclides. How many mCi are in the vial on Oct. 12 at 0900 PST? The total volume of the solution is 0.20 mL. What is its concentration in mCi/mL on Oct. 12 at 0900 PST?

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A solution of In-111 DTPA from the Amersham Corp. in Great Britain arrives in your
department with the following calibration data:
Activity
Volume
Date
Time
10.0 MBq
0.20 mL
Oct. 15
1200 PST
Look up the half-life of In-111 in your textbook or the Chart of the Nuclides.
How many mCi are in the vial on Oct. 12 at 0900 PST?
The total volume of the solution is 0.20 mL. What is its concentration in mCi/mL on Oct. 12 at
0900 PST?
Transcribed Image Text:A solution of In-111 DTPA from the Amersham Corp. in Great Britain arrives in your department with the following calibration data: Activity Volume Date Time 10.0 MBq 0.20 mL Oct. 15 1200 PST Look up the half-life of In-111 in your textbook or the Chart of the Nuclides. How many mCi are in the vial on Oct. 12 at 0900 PST? The total volume of the solution is 0.20 mL. What is its concentration in mCi/mL on Oct. 12 at 0900 PST?
Expert Solution
Step 1

The half-life of In-111 according to the chart of nuclides is

 t1/2=67.2hrst1/2=67.224dayst1/2=2.8days

The hours between 12 Oct at 09:00PST to 15 Oct 12:00PST.

Hours, t=24+24+24+3t=75hr

The period number, n=75t1/2n=7567.2n=1.12

Initial activity, A0=10MBqA0=10×106Bq

Now activity on 12 Oct,

A=A02nA=10×106×21.12A=21.73×106BqA=21.73×1063.17×1010CiA=0.685mCi

 

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