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The relative frequency table describes whether a group of employees from an accounting firm watch television on workdays and non-workdays. Watch TV Do Not Watch TV Workday 0.74 Not a Workday 0.13 0.11 0.02 For these employees, are watching television and a workday approximately independent? Justify the answer with probabilities. The events are approximately independent because 0.871 ≈ 0.870. The events are not independent because 0.871 = 0.870. The events are approximately independent because 0.851 # 0.870. The events are not independent because 0.851 # 0.870.

The relative frequency table describes whether a group of employees from an accounting firm watch television on workdays and non-workdays. Watch TV Do Not Watch TV Workday 0.74 Not a Workday 0.13 0.11 0.02 For these employees, are watching television and a workday approximately independent? Justify the answer with probabilities. The events are approximately independent because 0.871 ≈ 0.870. The events are not independent because 0.871 = 0.870. The events are approximately independent because 0.851 # 0.870. The events are not independent because 0.851 # 0.870.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The relative frequency table describes whether a group of employees from an accounting firm watch television on workdays and non-workdays. Watch TV Do Not Watch TV Workday 0.74 Not a Workday 0.13 0.11 0.02 For these employees, are watching television and a workday approximately independent? Justify the answer with probabilities. The events are approximately independent because 0.871 ≈ 0.870. The events are not independent because 0.871 = 0.870. The events are approximately independent because 0.851 # 0.870. The events are not independent because 0.851 # 0.870.
Transcribed Image Text:The relative frequency table describes whether a group of employees from an accounting firm watch television on workdays and non-workdays. Watch TV Do Not Watch TV Workday 0.74 Not a Workday 0.13 0.11 0.02 For these employees, are watching television and a workday approximately independent? Justify the answer with probabilities. The events are approximately independent because 0.871 ≈ 0.870. The events are not independent because 0.871 = 0.870. The events are approximately independent because 0.851 # 0.870. The events are not independent because 0.851 # 0.870.
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