The reinforced concrete column isreinforced with 6 – 28 mm Ø bars as shown. Steel yield strength fy = 414 MPa and concrete strength fc’ = 21 MPa.  Determine the nominal balanced load. a. 1721.252 kN c. 1821.225 kN b. 1921.253 kN d. 1521.522 KN Determine the nominal balanced eccentricity. a. 362.544 mm c. 352.544 mm b. 372.544 mm d. 382.544 mm Determine the nominal balanced moment. a. 677.326 kN.m. c. 777.321 kN.m. b. 312.852 kN.m d. 563.285 kN.m.

Q: Find roller support reaction

A: Given data : Point load =3 KN Point load=4 KN Point load=3 KN   To find : Roller support reaction

Q: 10 KN 15 KN 10 KN E. 0.9 m p.9m A B IF 1.2m 1.2m 1.2m 1.2m

A:

Q: 5-91. The A992 steel shaft made from two segments. AC has a diameter of 0.5 in. and CB has a…

A: Diameter of AC shaft =0.5 in Diameter of CB shaft =1.0 in Uniform distributed torque =60 lb·in/in…

Q: Draw Mohr's circle and find: 1) Principle stresses and their direction. 2) Maximum Shear stress and…

A:

Q: Calculate axil force due to dead and live load in three different columns A1, A2, C3  in all levels.…

A:

Q: w= 16 kN/m P 64 kN M = 20 kN-m acting clockwise on the end of the 6.1 meters cantilever beam,…

A:

Q: Prestress force (at transfer). P = 2000 kN, is applied at 50mm below centroid. Losses between…

A:

Q: 9. The forces F1 & F2 equal 490 ton and 100 kN respectively. Find the ratio between the first to…

A: We know from Archemedis principleP1=P2F1A1=F2A2

Q: A beam ABC with an overhang at one end supports a uniforms load of 12 kN/m and a concentrated load…

A:

Q: A B C D 40 kN.m 60 kN•m E OK 30 kN-m 50 kN-m

A:

Q: 01// An interior Two-way slab panel 6.0 m * 7.2m carry a live load 10 kN/m². The slab thickness is…

A:

Q: P2 Examination Questionnaire.odf - Nitro Pro 10 CLOUD HELP Situation 2 | Beam ABCDEFG below is…

A: Hi! Thank you for the question As per the honor code, We’ll answer the first question since the…

Q: 15 KN 10 KN 10 KN 1.0m 1.0 m H RAX 2.0m 20m 2.0 m 2.0 m 5 KN REY RAy

A: Solve for the forces of members CG, GH, AH, BC, BG, BH, and AB

Q: equally distributed to the shorter sides of the column. The centroid of the bars are 76 mm from the…

A:

Q: Determine the maximum moment at C, in kN-m. O 67.5 kN.m O 70 KN-m O 75 kN.m O 82.5 kN.m

A:

Q: 1.2m 1.2m

A: Dead load on purlin , =800×1.2=0.96 kN/m Live load on purlin, =1000×1.2=1.2 kN/m Now calculate the…

Q: short direction (assume Ø 10mm). Use

A:

Q: SITUATION II: A reinforced concrete beam 350mm and effective depth 540mm is used as a cantilever on…

A: All answer options are boxed.

Q: 2. Analyze the given Complex Frame by Substitution S KN 10 KN 30 30 6 m 30 30 -3 m Tension or…

A:

Q: 6-110. The 65-mm-diameter steel shaft is subjected to the two loads. Determine the maximum bending…

A: Given data:Shaft diameter  = 65 mmLoad 4 KN at an angle 30o from y-axis

Q: Q Forthe fvamin fig determine Veaction at supports ' So

A: Free Body Diagram of the given problem:

Q: G 67.5 kN 3.6 m -D -112.5 kN E 3.6 m IA B C 6 m +4.5 m Use portal method to analyze the frame.…

A:

Q: Calculate Tension BD if P = 100 kN. -1.5 m 1m 1 2 m D 250 N 15m- B 2.5m ...

A:

Q: drew the sher forn a) Expre the internal shear d m in e diagrs for the beam shwe ofs and the 4000 N…

A:

Q: Name four zero force members in the Figure. 6 kN 900 N- 2 m 2 m SE B.

A: Given- Trus s diagram with different loads

Q: 25M meter of the column in the ne nber of diameter 28mm longitu

A: Given:- deadload=1530kN live load-1420kN 12mm dimaeter  f'c=30MPa fy=425MPa To find:- a) diameter of…

Q: 6-05kN 6.VY KN 3.55m 3.XY m 6 kN E 3.YZ m 3.55m B 3.VY m 3.05m 8.ZY KN 8.55kN

A:

Q: 4- Is this a safe beam under the action of 120 kN.m moment? d= 55cm, by-32cm, n=15. C25: Allowable…

A: allowable stress : Civil engineers utilize a design philosophy known as permissible stress design.…

Q: 1028 //In a reinforced concrete beam, b = 500 mm,d = 750mm, X ₁ = 6000 mm², and n=10. What are the…

A:

Q: KN/M B Jom.

A:

Q: Design of Singly Reinforced Beams  1. A simply supported beam is 6 meters long and is reinforced as…

A: Given data: As=4×π4×252=1963.495 mm2d=400 mmb=250 mmfc'=35 MPafy=400 MPaL=6 mDL=26 kN/m

Q: 12kn/m 1okn/m section: 350 B 50 P: 600KN, e= 20mm CASSUme 10%. losses) From the figure shown,…

A:

Q: Figure (101) the allowable bearing stress for the maternal under the supports at A and B 14MPa,…

A: Given:- The allowable bending stress at A and B = σallow = 1.4 MPa The magnitude of the uniform load…

Q: 1. Draw the shear and moment Diagram of the beam. 2. Determine the maximum compressive stress of the…

A:

Q: Given the following properties of a rectangular concrete beam: b = 300mm, d = 425mm, f'c = 28 MPa,…

A: The ultimate moment is the moment which acting with its capacity on the beam. Mathemtically,It is…

Q: HwO Redvaw the shear Stressdlistribution diagram for the H.w above, if the beam Section is change to…

A:

Q: Ex (2): A E= 2 * 108 KN & 1=1 * 104 mª m² Required: Ac,v = 15 kN/m " 6 m ....mm eD= .........rad 150…

A:

Q: 1 kN F 1 kN J B C E G 5 kN 5 kN 5 kN 1 kN D 1 kN I K -6 panels @ 5 m = 30 m- 1 kN h=8m LA 12.…

A:

Q: 2) arfoce Aprismatic bor is'under tenstan, 24N 24N bar has a sizeof (3cm XaCm) in width ond de pth…

A: P=24N Theta =30o

Q: Determine the design positive and negative moments of the beam shown. The dead and live loads are…

A:

Q: Determine bar force member EF 10 KN 15 KN 10 KN D E 0.9 m 0.9m A B G IF 1.2m1.2m 1.2m 1.2m

A:

Q: H.W. Determine the horizontal and vertical components of force at pins A and D. D. Ans A, = 24.0 kN…

A: The FBD of the beam:

Q: Solve the beamb And reachon: by osng se method and don hear pree and Bonding Morent aogr bkNm BEN/m…

A: Support Reactions: ∑Fy = 0 ⇒ RA + RB = 3×6 + 12×6-3×3RA + RB = 22.5 kN..........(1)∑Mc = 0 ⇒ RA×6 -…

Q: First moment of area Q in mm'. 3,218.75 x10³ mm³ Maximum flexural shear stress in MPa. 0.516 MPa

A: Given :

Equilibrium and Support Reactions

Civil engineers deal with structures that are composed of several members connected or with individual members such as beams and columns. To analyze such structures, the condition of statics must be applied. Under the static condition, the members are considered to be in equilibrium under the action of forces, that is, the members are assumed to be having negligible velocity.