The reduction potential to the metal of Ba 2+ is -1.57 V and that of Cu 2+ is +0.34 V. The cell potential for the reaction Ba(s) + Cu 2+ (aq) → Ba 2+ (aq) + Cu(s) is therefore: a.(+1.57) + (+0.34) b.(+1.57) + (-0.34) c.(-1.57) + (+0.34) d.2 x (-1.57) + 2 x (0.34) e.(-1.57) + (0.34)

Reduction potential of Ba2+ = -1.57 V Reduction potential of Cu2+ = +0.34 V The net cell reaction…

Answered: The reduction potential to the metal of…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The reduction potential to the metal of Ba ²⁺ is -1.57 V and that of Cu ²⁺ is +0.34 V. The cell potential for the reaction Ba(s) + Cu ²⁺ (aq) → Ba ²⁺ (aq) + Cu(s) is therefore:

	a.	(+1.57) + (+0.34)
	b.	(+1.57) + (-0.34)
	c.	(-1.57) + (+0.34)
	d.	2 x (-1.57) + 2 x (0.34)
	e.	(-1.57) + (0.34)

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