The reduction of NO to N, with H,;2NO(g) + 2H2(g) = N2(g) + 2H,0(g), is found to have the following experimentally determined rateequation: Rate =k[NO]²[H,]If the concentration of NO and H, were doubled then the rate of the reaction would:Decrease four foldIncrease four foldIncrease two foldIncrease eight fold

Given: Chemical Equation 2 NO (g) + 2 H 2 (g) → N 2 (g) + 2 H 2O (l) Rate = k[NO]2[H2]

The reduction of NO to N, with H: 2NO(g) + 2H2(g) = N2(g) + 2H,0(g), is found to have the followving experimentally determined rate equation: Rate = k[NO] [H;] If the concentration of NO and H, were doubled then the rate of the reaction would: Decrease four fold Increase four fold O Increase two fold Increase eight fold

The reduction of NO to N, with H: 2NO(g) + 2H2(g) = N2(g) + 2H,0(g), is found to have the followving experimentally determined rate equation: Rate = k[NO] [H;] If the concentration of NO and H, were doubled then the rate of the reaction would: Decrease four fold Increase four fold O Increase two fold Increase eight fold

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The decomposition of N₂O, can be described by the equation 2N₂O5(soln) -> - →→→ 4NO₂ (soln) + O₂(g) Consider the data in the table for the reaction at 45 °C in carbon tetrachloride solution. t (s) 0 225 556 755 average rate of reaction: PRE average rate of reaction: [N₂O,] (M) Given the data, calculate the average rate of reaction for each successive time interval. What is the average rate of reaction for the time interval from 0 s to 225 s? average rate of reaction: 2.381 2.067 What is the average rate of reaction for the time interval from 225 s to 556 s? TOOLS 1.678 1.481 What is the average rate of reaction for the time interval from 556 s to 755 s? a M/s M/S M/s Rese Question Sou 994
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