Now, let's say we have two reactants involved in the rate law, like this: A+B C + D The rate law might look like this: rate = K[A]²[B] We would say this reaction is 2nd order with respect to A since it depends on the concentration of A to the 2nd power. It is 1st order with respect to B since it depends on the concentration of B to the 1st power. What is the overall order for this reaction?

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Now, let's say we have two reactants involved in the rate law, like this:
C + D
The rate law might look like this:
A+B
rate = K[A]²[B]
We would say this reaction is 2nd order with respect to A since it depends on the concentration of A to the 2nd
power. It is 1st order with respect to B since it depends on the concentration of B to the 1st power. What is the
overall order for this reaction?
Transcribed Image Text:Now, let's say we have two reactants involved in the rate law, like this: C + D The rate law might look like this: A+B rate = K[A]²[B] We would say this reaction is 2nd order with respect to A since it depends on the concentration of A to the 2nd power. It is 1st order with respect to B since it depends on the concentration of B to the 1st power. What is the overall order for this reaction?
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