The rectangular coordinates of a particle which moves with curvilinear motion are given by x = 10.75t +2.25t² – 0.45t³ and y = 6.90 + 17.43t - 2.62t², where x and y are in millimeters and the time t is in seconds, beginning from t = 0. Determine the velocity v and acceleration a of the particle when t = 8 s. Also, determine the first time that the velocity of the particle makes an angle of 30° with the positive x-axis. Answers: V= a= t= (i (i i+ i i+ S i j) mm/s j) mm/s²

The rectangular coordinates of a particle which moves with curvilinear motion are given by x = 10.75t +2.25t² – 0.45t³ and y = 6.90 + 17.43t - 2.62t², where x and y are in millimeters and the time t is in seconds, beginning from t = 0. Determine the velocity v and acceleration a of the particle when t = 8 s. Also, determine the first time that the velocity of the particle makes an angle of 30° with the positive x-axis. Answers: V= a= t= (i (i i+ i i+ S i j) mm/s j) mm/s²

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

6.4 and 3.2 are incorrect. Find v and a
The car travels around the portion of a circular track having a radius of r = 500 ft such that when it is at point A it has a velocity of 2 ft/s, which is increasing at the rate ofa = 0.002t in ft/s, where t is in seconds. Determine the magnitudes of its velocity and acceleration when it has travelled three-fourths the way around the track. O v = 36.83 ft s^-1 ; a = 2.74 ft s^-2 O v = 28.11 ft s^-1 ; a = 1.61 ft s^-2 O v = 17.71 ft s^-1 ; a = 0.68 ft s^-2 O None of the choices
The velocity of a particle is V and is constant. It moves counterclockwise on a circle with center "O" and radius R. Draw the circle. When the particle is in the vector R position, draw vector R, vector V, vector A, and vector da/dt(time derivative of acceleration).
A particle is moving in a circular path with v = 8t m/s, where "t" is in seconds. If the circumference of the path is 9π cm. Find the magnitude of its total acceleration at time = 4 s.
The rectangular coordinates of a particle which moves with curvilinear motion are given by x = 10.00t + 1.50t² - 0.30t³ and y = 5.93 + 20.37t-2.76t², where x and y are in millimeters and the time t is in seconds, beginning from t = 0. Determine the velocity v and acceleration a of the particle when t = 6 s. Also, determine the first time that the velocity of the particle makes an angle of 27° with the positive x-axis. Answers: V= a = t = i i i i+ i i+ S j) mm/s j) mm/s²
٤٣ B/s ۱۰:۰۹ ص .in the direction of the force TO FO choose the correct answer The acceleration Vector in cartizan Cordinat writin by the formulla Ⓒazé x + j X+kŹ =¿Ÿ+K Ⓒă= cx+jŸ+k² @a=ix + ³y +kż a b с do time derivative of velocity is called acceleration rate velocity docs.google.com/forms/d/ तं
At t = 0 the coordinates of a particle are x = 0, y = 1.98 m. At a time 0.95 s later, its coordinates are x = 3.21 m, y = 4.20 m. Find the components of the particle's average velocity during this time interval. vx = vy =
حل كل السؤال
The position of a particle is given by i= (7.7t +7)i- 3tj+5k, where F in (m) and t in (s). The magnitude of the velocity (in m/s) at t= 19.6 s is:
The velocity of a particle moving in thex-y plane is given by (4.03i + 7.36j) m/s at time t = 3.64 s. Its average acceleration during the next 0.020 s is (2.2i + 2.6j) m/s?. Determine the velocity v of the particle at t = 3.660 s and the angle e between the average- acceleration vector and the velocity vector at t = 3.660 s. Answers: v= ( i i+ i j) m/s e =
PLEASE ANSWER QUICKLT AND WILL RATE HIGHLY *15
A particle moving in the x-y plane has a velocity v = 7.80i + 2.97j m/s at a certain instant. If the particle then encounters a constant acceleration a = 0.88j m/s², determine the amount of time which must pass before the direction of the tangent to the trajectory of the particle has been altered by 33º. Answer: t = i S