The reaction BC + d→"B+a+5.16 MeV occurs when 10 MeV deuterons impinge on carbon nuclei. What angle will be made by the directions with which the products of the reaction exit when: (a) The nuclei produced diverge symmetrically, (b) The a-particle comes out at a right angle to the direction of the neutron?
The reaction BC + d→"B+a+5.16 MeV occurs when 10 MeV deuterons impinge on carbon nuclei. What angle will be made by the directions with which the products of the reaction exit when: (a) The nuclei produced diverge symmetrically, (b) The a-particle comes out at a right angle to the direction of the neutron?
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