The reaction A → C was performed and the concentration vs. time data below collected. 4 time, s 0 1 2 Rate = k[A]* rate constant (without units) = = reaction order = 3 5 6 7 8 [A], mol/L 0.7041 0.4557 0.2950 0.1909 0.1236 0.07999 0.05177 0.03351 0.02169 Complete the rate law for the reaction by filling in the values for the rate constant and reaction order.

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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000 0
[A] vs Time
In[A] vs Time
1/[A] vs Time
Least Squares
Plot
In[A]
The reaction
A → C
was performed and the concentration vs. time data below collected.
3
time, s 0
[A], mol/L 0.7041 0.4557 0.2950 0.1909 0.1236 0.07999 0.05177 0.03351 0.02169
Complete the rate law for the reaction by filling in the values for the rate constant and reaction order.
1
Time, s
2
Rate = k[A]*
rate constant (without units)
reaction order =
4
5
6
7
8
Transcribed Image Text:000 0 [A] vs Time In[A] vs Time 1/[A] vs Time Least Squares Plot In[A] The reaction A → C was performed and the concentration vs. time data below collected. 3 time, s 0 [A], mol/L 0.7041 0.4557 0.2950 0.1909 0.1236 0.07999 0.05177 0.03351 0.02169 Complete the rate law for the reaction by filling in the values for the rate constant and reaction order. 1 Time, s 2 Rate = k[A]* rate constant (without units) reaction order = 4 5 6 7 8
Expert Solution
Step 1

The integrated rate law for the Zero order reaction is  [A]=-kt+[A]o.  If a plot of [A] vs time (t) is a straight line then the reaction is zero order with respect to "A".

The integrated rate law for the first order reaction isln[A]=-kt+ln[A]o. If a plot of ln[A] vs time (t) is a straight line then the reaction is first order with respect to "A".

The integrated rate law for the second order reaction is 1/[A]=kt+1/[A]o. If a plot of 1/[A] vs time (t) is a straight line then the reaction is second order with respect to "A".

 

 

 

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