The reaction 2NO (g) + 02 (g) → 2NO2 (g) has the third-order rate law: rate = k[NO]2 [O2], where k = 25 M ²s1. Under the condition that [NO] =2 [O2], 8kt + 1 the integrated rate law is What are the concentrations of NO, O2, and NO2 after 120.0 s if the initial concentrations are NO] = 2.20×10-2 M and [O2] = 1.10×10-2 M ? Express your answer using two significant figures. Enter your answers numerically separated by commas. ? NO], [02], [NO2] = M

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The reaction 2NO (g) + 02 (g) → 2NO2 (g) has the third-order rate law:
rate = k[NO]2 [O2], where k = 25 M ²s=1. Under the condition that [NO] =2 [O2],
8kt +
1
the integrated rate law is
What are the concentrations of NO, 02, and NO2 after 120.0 s if the initial concentrations are NO] = 2.20×10-2 M and [O2] = 1.10×10-2 M ?
Express your answer using two significant figures. Enter your answers numerically separated by commas.
?
[NO], [O2], [NO2] =
M
Transcribed Image Text:The reaction 2NO (g) + 02 (g) → 2NO2 (g) has the third-order rate law: rate = k[NO]2 [O2], where k = 25 M ²s=1. Under the condition that [NO] =2 [O2], 8kt + 1 the integrated rate law is What are the concentrations of NO, 02, and NO2 after 120.0 s if the initial concentrations are NO] = 2.20×10-2 M and [O2] = 1.10×10-2 M ? Express your answer using two significant figures. Enter your answers numerically separated by commas. ? [NO], [O2], [NO2] = M
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